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3 years ago

What is the least common denominator of 3/10 and 1/2 help asp

Mathematics

2 answers:

Llana [10]3 years ago

6 0

Answer:

the least common denomonater is 10

Step-by-step explanation:

3/10 = 3/10 × 1/1 = 3/10

1/2 = 1/2 × 5/5 = 5/10

Please give me brainliest! hope this helps god bless:)

BabaBlast [244]3 years ago

3 0

LSD is 20. Your welcome

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The vertex of ∠A B C is located at the origin. Point A is located at (5,0) and Point C is located at (0,2). How can ∠A B C be cl

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As the angle is greater than 0° and less than 90°, then the angle ABC is acute. (Answer: A)

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1 year ago

Solve the equation 3/8p=9

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3 years ago

100 students were asked to ll out a form with three survey questions, as follows: H: Honor Roll

poizon [28]

Answer:

1. 45

2. 9

3. 11

4. 17

Step-by-step explanation:

The computation is shown below:

Given that

28 checked H

26 checked C

14 checked D

8 checked H and C

4 checked H and D

3 checked C and D

2 checked all.

Based on the above information

N(H)=28

N(C) 26

N(D) 14

N(H∪C) = 8

N(H∪D) = 4

$N(C\cup D)=3$

$N(H\cup C\cup D)=2$

We know that

$Total=N(H)+N(C)+N(D)-N(H\cup C)-N(H\cup D)-N(C\cup D)+N(H\cup C\cup D)$

= 28 + 26 + 14 - 8 - 4 - 3 + 2

= 55

1. The students who didnt check any kind of the box is

= 100 - 55

= 45

2) Students who checked exactly two boxes is

$= N(H\cup C)+N(H\cup D)+N(C\cup D)-3N(H\cup C\cup D)$

= 8 + 4 + 3 - 6

= 9

3) Students who checked a minimum of two boxes

$= N(H\cup C)+N(H\cup D)+N(C\cup D)-2N(H\cup C\cup D)$

= 8 + 4 + 3 - 4

= 11

4) Given N(C) = 26

Now we have to deduct N(C∪D) and N(H∪C) as it could be checked aside from the club

= 26 - 8 - 3

= 15

Here the $N(H\cup C\cup D)$ could be deducted twice under both categories so it would be added one time to neutralize

= 15 + 2

= 17

6 0

3 years ago