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Nina [5.8K]
3 years ago
14

Which is a possible leading term for the graph shown? 2x3 –2x3 2x4 –2x4

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
6 0

Answer:

C. 2x^4

Step-by-step explanation:

Just took it. Edg 2020. Hope this helps :)

Y_Kistochka [10]3 years ago
4 0

Answer:

2x^4

Step-by-step explanation:

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Two skiers are 30 kilometers apart and head towards each other. They meet in 2 hours. If the second skier is 5 kilometers per ho
DENIUS [597]

Answer:

Speed of first skier = 5 km/h

Speed of second skier = 10 km/h

Step-by-step explanation:

Given:

Distance between skiers = 30 km

Time after which they meet = 2 hours

Second skier is 5 km/h faster than the first skier.

To find speed of each skier.

Solution:

Let the speed of first skier be in km/h =x

<em>Distance covered in km 2 hours will be = Speed\times time=x\times 2=2x\ km</em>

Speed of second skier in km/h can be given as = x+5

<em>Distance traveled by second skier after 2 hours will be = Speed\times time=(x+5)\times 2=(2x+10)\ km   [Using distribution]</em>

Since, the skiers were 30 km apart initially, so the total distance covered by both of them when they meet after 2 hours will be = 30 km

Thus, we have:

2x+2x+10=30

Solving for x

4x+10=30

Subtracting both sides by 10.

4x+10-10=30-10

4x=20

Dividing both sides by 4.

\frac{4x}{4}=\frac{20}{4}

x=5

Speed of first skier = 5 km/h

Speed of second skier = 5+5 = 10 km/h

8 0
3 years ago
4(1-2b)+7b-10
likoan [24]

Answer:

if you're simplifying, it should be = -1b - 6

Step-by-step explanation:

1. 4(1-2b) + 7b -10 solve the parenthesis

2. 4 <u>- 8b</u> <u>+ </u><u>7b</u> - 10 combine like(same) terms

3. <u>4</u> - 1b <u>- 10</u> same as 2.

4. -1b - 6

5 0
3 years ago
Can someone please help me with this geometry please?
Crank

Answer:

<u>5x+13</u> ÷ 36 = 6x-2 ÷ 30

5x+13 ÷ 6 = 6x-2 ÷ 5

25x+65=36x-12

11x=77 → x=7

<u />

Step-by-step explanation:

5 0
3 years ago
Can someone please factor this 15x^2-17x-18
Rudiy27
Answer is 18 and value of x is 0



5 0
3 years ago
Can you help me with this please ​
krek1111 [17]

Answflasvkdiuihrytiy\ih\j

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