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kumpel [21]
3 years ago
13

Represent the following sentence as an algebraic expression, where "a number" is the

Mathematics
1 answer:
kenny6666 [7]3 years ago
8 0
Answer. x>1
Explanation. when “x” is greater than one. We use the greater than symbol and use “x” as the variable.
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Simplify<br><br> √12m • √15m<br><br> = [1] m √[2]
Elodia [21]

Answer:

  6m√5

Step-by-step explanation:

  √(12m)·√(15m) = √(180m²) = √(5·(36m²)) = √5·√(6m)²

  = 6m√5 . . . . . . for m ≥ 0

8 0
3 years ago
1-(-4) ,, (-4) is squared outside the parentheses
Naddika [18.5K]
1-(-4)^2
1-(-4 times -4)
1-(16)
1-16
-15
5 0
3 years ago
Branden and Pete both play running back. Branden carries the ball 75 times for 550 yards and Pete had 42 carries for 380 yards w
mars1129 [50]

Answer:

Pete runs farther per carry.

Step-by-step explanation:

Given:

Branden and Pete both play running back.

Branden carries the ball 75 times for 550 yards.

Pete had 42 carries for 380 yards

Question asked:

Who runs farther per carry ?

Solution:

First of all we find each boy's distance covered per carry:-

<u>For Branden</u>

Branden carries the ball 75 times for = 550 yards.

Branden carries the ball 1 time for = \frac{550}{75} =7.34\ yard

<u>For Pete </u>

Pete carries 42 times for = 380 yards

Pete carries 1 time for = \frac{380}{42} =9.05\ yards

As Pete runs 9.05 yards for 1 carry while Branden runs 7.34 yards for 1 carry, hence Pete runs farther per carry.

3 0
3 years ago
Help and explain how you got it.<br><br> no trolling or report!
Galina-37 [17]

Answer:

I am 100% confident in my calculations. I'm not 100% sure about interpreting. Sorry I can't be of more help.

Part A:

Median: 4.5

IQR: 3.5

Mode: 6

I think the median/IQR is a better measure of center and variability because the range of data is so big (10 - 0 = 10), and the data skews to the right with the 6s.

Part B:

I would say no. It is the one that occurs most frequently, but there are many more times she rides less than 6, which is why the median is 4.5

Step-by-step explanation:

Mean: 4.714

MAD: 2.43

Median: 4.5

IQR: 3.5

Mode: 6

the number set in order:

0, 2, 2, 2.5, 2.5, 3, 4, 5, 6, 6, 6, 8, 9, 10

The median (middle number) is two numbers: 4 and 5, so the median is 4.5

The first quartile/Q1 (middle of the bottom half of data) is 2.5, the third quartile/Q3 (middle of the top half of data) is 6. So the IQR (interquartile range) is 6 - 2.5 = 3.5

The mean is the sum of the numbers divided by the quantity of the numbers, so 66/14 = 4.714

the mean absolute deviation is found by calculating the mean, and then finding the absolute value of the difference between each number of the set and the mean...then adding those together and finding the mean of that set. Labor intensive, but that's 34/14 = 2.42857143

4 0
3 years ago
Carmen drew line A and line B in the two scatter plots shown. one scatter plot contains 12 points indicating a negative correlat
blondinia [14]

The true statement is that only line A is a well-placed line of best fit

<h3>How to determine the true statement?</h3>

The scatter plots are not given. However, the question can still be answered

The features of the given lines of best fits are:

<u>Line A</u>

  • 12 points in total
  • Negative correlation
  • Passes through the 12 points with 6 on either sides

<u>Line B</u>

  • 12 points in total
  • Positive correlation
  • Passes through the 12 points with 8 and 4 in either sides

For a line of best fit to be well-placed, the line must divide the points on the scatter plot equally.

From the given features, we can see that line A can be considered as a good line of best fit, because it divides the points on the scatter plot equally.

Read more about line of best fit at:

brainly.com/question/14279419

#SPJ1

4 0
2 years ago
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