Explain why a cross section of a polyhedron does not always match the base of that polyhedron.
1 answer:
Explanation:
If the polyhedron is a prism and the cross sections are parallel to the base, then the cross section will match the base. Under other conditions, the cross section may not match the base.
For example, the first attachment is a figure of a cube. Cross sections are shown that have the shape of a triangle, trapezoid and hexagon. Other cross sections are possible.
A general polyhedron need not be regular and need not have any cross section congruent to the base (except the cross section that <em>is</em> the base). For some polyhedrons, it may be difficult even to identify the base. See the second attachment.
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Answer:
Step-by-step explanation:
Well we can simplify the numerator, by multiplying the 4 by the 6 and the m^3 and m^4 (add the exponents, explained in one of my previous answers I think)
This gives us the fraction:
We can now divide the m^7 by m^2 by subtracting the exponents, and the reason why this works, is you're simply cancelling out the m's, If we express this in expanded form we have the following fraction:
Since there is two m's in the denominator and there is also two (more than two) m's in the numerator, we can cancel those two m's out, and we get the fraction:
which can be simplified in exponent form as:
, now all we have to do is divide the 24 by the 3, to get 8
This gives us the answer: