i-okay,whats yoour problem? maybe i can help :D
9514 1404 393
Answer:
D . . . (best of the erroneous choices)
Step-by-step explanation:
Solving the first equation for x, we get ...
√(y -1) ≥ x
Solving the second equation for x, we get ...
x > 3
Substituting for x, we have ...
√(y -1) > 3
y -1 > 9
y > 10
Ordered pairs that are in the solution set will have coordinates ...
x > 3, y > 10
In interval notation that looks like ...
x ∈ (-∞, 3) and y ∈ (10, ∞)
The closest answer choice is the last one.
_____
You will note that x must be strictly greater than 3, so y cannot be equal to 10. The offered choice is in error on that point.
__
You will also note that y is dependent on x. That is, one cannot pick a value of y greater than 10 independently of the value of x. In that sense, the solution is not "the set of all ordered pairs such that [x and y have independent limits]". Rather, it is the set of all ordered pairs such that √(y -1) ≥ x > 3.
Answer: D
(2x)^2 + 2(3•2x) + 3^2
4x^2 + 2(6x) + 9
4x^2 + 12x + 9
Answer:
80%
Step-by-step explanation:
20000. take out 3 zeros from both numbers and you get 20 and 16. 20 is 4 times 5 and 16 is 4 times 4 if 20 is 100% then 4 over 5 is 80%
So set up the equations
q-12=d
25q+10d=1105
plug in q-12 as d in the second equation:
25q+10q-120=1105, then simplify:
35q=1225
q=35
since there's 12 fewer dimes, we know that there's 23 dimes and 35 quarters.