Answer:
T₂ = 421.4 K
Step-by-step explanation:
The temperature, T, of a given mass of gas varies inversely with its Volume,V.
We have,
V₁ = 98 cm³, T₁ = 28° C = (28+273) K = 301 K
V₂ = 70 cm₃
We need to find the new temperature of the gas. Using the above relation to find T₂.
Hence, the required temperature of the gas is 421.4 K.
Answer:
![\displaystyle [-8, -10]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B-8%2C%20-10%5D)
Step-by-step explanation:
12 = x - 2[3x + 14]
12 = x - 6x - 28
12 = −5x - 28
+ 28 + 28
____________
[Plug this back into both equations above to get the y-coordinate of −10]; 
I am joyous to assist you anytime.
The coefficients in the equation (-x)(3y)(-2x) are the constants -1, 3, and -2.
In order to simplify and determine only one coefficient <span>we should multiply all three constants together to get only one numerical constant .
</span><span>The commutative law</span> says hat you can rearrange a multiplication any way you want. so, (-1)*3*(-2)=(-3)*(-2)=6
The equation can be also simplified written as:
6x^2y
None of the option is the solution.
The answer would be:
X = -1
