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BARSIC [14]
3 years ago
5

a computer store builds custom computers by allowing customers to choose 1 of 4 different CPU's. 1 of 8 hard drives, and 1 of 3

video cards how many different computers are possible
Mathematics
2 answers:
Gelneren [198K]3 years ago
8 0

Answer: 96

Step-by-step explanation:

Given : Number of different CPU's = 4

Number of different hard drives = 8

Number of different video cards = 3

Then by Fundamental principle of counting , the number of different computers are possible is given by :_

4\times8\times3=96

Therefore, the number of possible different computers= 96

Lelechka [254]3 years ago
3 0
You multiply the possibilities.

4*8*3 = 96 possibilities.
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Find the quotient. 22x2y2 ÷ 11x2y2
Sloan [31]

Quotient = 2

Solution:

Given expression is 22x^2y^2\div11x^2y^2.

To find the quotient.

22x^2y^2\div11x^2y^2=\frac{22x^2y^2}{11x^2y^2}

In numerator 22 can be written as 2 × 11.

\frac{22x^2y^2}{11x^2y^2}=\frac{2\times11x^2y^2}{11x^2y^2}

Take common term out in the numerator and denominator.

\frac{22x^2y^2}{11x^2y^2}=\frac{(11x^2y^2)(2)}{11x^2y^2}

Common terms in the numerator and denominator will be cancelled.

\frac{22x^2y^2}{11x^2y^2}=2

Hence the quotient is 2.

4 0
3 years ago
If x is equal to 2 minus root 3 find the value of x minus one upon X whole cube
Kamila [148]
"2 minus root 3"  =>  2 - sqrt(3)

x does not appear here.  That could cause a problem.  

Unsure of what you mean by "x minus one upon X whole cube."  Would you please go back to the original question and ensure that you have copied it down precisely.  Without "x" in your equation, there's nothing to solve for.


8 0
3 years ago
Mr. Kellow can lay 279 yards of sprinklers in 6 hours. How many yards of sprinkler can he lay in 1 hour?
Verizon [17]

Answer:

46.5 yards

Step-by-step explanation:

Simply divide the number of yards by the number of hours

279/6 = 46.5

He can lay 46.5 yards in one hour

3 0
3 years ago
Read 2 more answers
11.) Evaluate the expression.
Setler [38]

Answer:

- 116

Step-by-step explanation:

Given

28 - ( \sqrt{144} )²

= 28 - (12)²

= 28 - 144

= - 116

6 0
3 years ago
Each student at some college has a mathematics requirement M (to take at least one mathematics course) and a science requirement
Furkat [3]

all students = 150

M = 60

S = 45

M and S = 25

(a) At least one of the two requirements:

M or S = M + S - (M and S) = 60 + 45 - 25 = 80

(b) Exactly one of the two requirements:

(M or S) - (M and S) = 80 - 25 = 55

(c) Neither requirement:

(all students) - (M or S) = 150 - 80 = 70

8 0
3 years ago
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