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lora16 [44]
3 years ago
11

10 times as many as 5 tens is 5thousand

Mathematics
1 answer:
insens350 [35]3 years ago
3 0

Answer:

This question does not make sense for very specific reasons

Step-by-step explanation:

1. 5,000 does not look like 5thousand

2. 10 times as many as 5 tens is not really a question at all

3. the question itself already contains the answer 5,000

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Evaluate the limits<br><br>​
julsineya [31]

x > \ln(x) for all x, so

\displaystyle \lim_{x\to\infty} (\ln(x) - x) = - \lim_{x\to\infty} x = \boxed{-\infty}

Similarly, \displaystyle \lim_{x\to\infty} (x-e^x) = - \lim_{x\to\infty} e^x = \boxed{-\infty}

We can of course see the limits are identical by replacing x\mapsto e^x, so that

\displaystyle \lim_{x\to\infty} (\ln(x) - x) = \lim_{x\to\infty} (\ln(e^x) - e^x) = \lim_{x\to\infty} (x - e^x)

You can also rewrite the limands to accommodate the application of l'Hôpital's rule. For instance,

\displaystyle \lim_{x\to\infty} (x - e^x) = \ln\left(\exp\left(\lim_{x\to\infty} (x - e^x)\right)\right) = \ln\left(\lim_{x\to\infty} e^{x-e^x}\right) = \ln\left(\lim_{x\to\infty} \frac{e^x}{e^{e^x}}\right)

Using the rule, the limit here is

\displaystyle \lim_{x\to\infty} \frac{(e^x)'}{\left(e^{e^x}\right)'}  = \lim_{x\to\infty} \frac{e^x}{e^x e^{e^x}} = \lim_{x\to\infty} \frac1{e^{e^x}} = 0

so the overall limit is

\displaystyle \lim_{x\to\infty} (x - e^x) = \ln\left(\lim_{x\to\infty} \frac{e^x}{e^{e^x}}\right) = \ln(0) = \lim_{x\to0^+} \ln(x) = -\infty

6 0
2 years ago
A juice box is constructed from a cardboard net. How many inches of cardboard are needed for each juice box?
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Step-by-step explanation:

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3 years ago
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y-2 = -4(x-1) ... plug in the given info; solve for y

y-2 = -4x+4

y = -4x+4+2

y = -4x+6

Answer is choice C

5 0
3 years ago
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For what shape? Rectangular prism?
4 0
3 years ago
Solve using DISTANCE = RATE X TIME
wariber [46]
The rate is speed which 50m/h. so he left the home at 10:00 and arrived at noon which 12:00pm so the difference is 2 hours which means he took 2 hours to get there.
to find the distance. 
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6 0
3 years ago
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