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mr_godi [17]
3 years ago
9

Help pleaseeeeeee!!!

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0

Answer:

Second one.

Step-by-step explanation:

Review that one before you go to the next one.

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What is the answer for these questions?
PIT_PIT [208]

Answer:

a.) yes

b.) no

c.) yes

d.) yes

Step-by-step explanation:

5 0
2 years ago
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If the right side of the equation dy dx = f(x, y) can be expressed as a function of the ratio y/x only, then the equation is sai
melomori [17]

Answer:

 y = x*sqrt(Cx - 1)

Step-by-step explanation:

Given:

                                  dy / dx = (x^2 + 5y^2) / 2xy

Find:

Solve the given ODE by using appropriate substitution.

Solution:

- Rewrite the given ODE:

                               dy/dx = 0.5(x/y) + 2.5(y/x)

- use substitution y = x*v(x)

                               dy/dx = v + x*dv/dx

- Combine the two equations:

                                v + x*dv/dx = 0.5*(1/v) + 2.5*v

                                x*dv/dx = 0.5*(1/v) + 1.5*v

                                x*dv/dx = (v^2 + 1) / 2v

-Separate variables:

                                 (2v.dv / (v^2 + 1) = dx / x  

- Integrate both sides:

                                 Ln (v^2 + 1) = Ln(x) + C

                                 v^2 + 1 = Cx

                                 v = sqrt(Cx - 1)

- Back substitution:

                                (y/x) = sqrt(Cx - 1)

                               y = x*sqrt(Cx - 1)

                         

3 0
3 years ago
Sam divided A rectangle into 8 congruent rectangles that each have the area shown. what is tge area of tge rectangle befoe sam d
aniked [119]

No area is shown. So befoe sam divided it,
the area of tge original rectangle was . . .

     8 x 0  =  zero .


3 0
3 years ago
Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2
Agata [3.3K]
\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------

\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left(  \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o
8 0
3 years ago
QuestiuI4
4vir4ik [10]

Answer:

The new volume is 14,850cm³

Step-by-step explanation:

Given

Volume of a rectangular prism = 550cm

Required

Value of volume when the dimensions are tripled.

The volume of a rectangular prism is calculated using the following formula.

V = lbh

<em>When Volume = 550, the formula is written as follows</em>

550 = lbh

<em>Rearrange</em>

lbh = 550

However, when each dimension is tripled.

This means that,

new length = 3 * old length

new breadth = 3 * old breadth

new height = 3 * old height

<em>Let L, B and H represent the new length, new breadth and new height respectively</em>

In other words,

L = 3l

B = 3b

H = 3h

Calculating new volume

New volume = LBH

Substitute, 3l for L, 3b for B and 3h for H;

V = 3l * 3b * 3h

V = 3 * l * 3 * b * 3 * h

V = 3 * 3 * 3 * l*b*h

V = 27 * lbh

Recall that lbh = 550

So,

V = 27 * 550

V = 14,850

Hence, the new volume is 14,850cm³

6 0
3 years ago
Read 2 more answers
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