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Nostrana [21]
3 years ago
5

Solve the inequality. 2(4 + 2x) ≥ 5x + 5? x ≤

Mathematics
2 answers:
LenKa [72]3 years ago
7 0

Answer:

x≤3

Step-by-step explanation:

there ya go :D

murzikaleks [220]3 years ago
3 0
Treat as an equality, except flip the sign direction when yo multiply or divide both sides by  a negative number

first distribute
2(4+2x)<u>></u>5x+5
distribute
8+4x<u>></u>5x+5
minus 4x fro both sides
8<u>></u>x+5
minus 5 from both sides
3<u>></u>x
x<u><</u>3

x is less than or equal to 3
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Cuál enunciado No es verdadero con respecto al valor de la varieble n en la siguiente ecuación?
aliina [53]

Answer:

es la c

Step-by-step explanation:

Explicación paso a paso:ya que para que de 0 tiene que ser un número negativo, tiene que ser el número inverso a 2/3, entonces n= -2/3 que tiene el mismo valor absoluto que  2/3

3 0
3 years ago
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Answer: CONFUSED LIKE REALLY CONFUSED BUT THANKS

Step-by-step explanation:

6 0
3 years ago
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The fence along the length of a ranch measures 4,450.5 meters and the fence along the width of a ranch measures 2,890 meters.
lawyer [7]
Given:Length = 4,450.5 metersWidth = 2,890 meters
1 kilometer = 1,000 meters
Length: 4,450.5 meters * 1km/1,000 meters = 4,450.5 km/1,000 = 4.4505km
Width: 2,890 meters * 1km/1,000 meters = 2,890 km/1,000 = 2.89 km
4.4505 km - 2.89 km = 1.5605 km
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3 0
3 years ago
Which property would allow you to use mental computation to simplify the problem 27 + 15 + 3 + 5? additive identity additive inv
Fofino [41]

Answer:

Commutative Property

Step-by-step explanation:

Additive Identity: If you add a real number to zero or add zero to a real number, then you get the same real number back.

Additive Inverse: When you add the same number but reversed sign, you get 0.

Commutative Property: a + b = b + a

Addition distributive property: a(b+ c) = ab + ac.

In this case, we use the commutative property:

27 + 15 + 3 + 5 = 27 + 3 + 15 + 5.

We know that 27 + 3 = 30 and 15 + 5 = 20, so we get 50 quickly using mental math.

5 0
3 years ago
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A scientist removed a sample of 39.1 grams of a chemical from a container. The sample was 5 3/4 grams less than 3/10 of the tota
Oksanka [162]

The first thing we must do for this case is to define variables:

x: the total mass of the chemical in the container

y: a sample of a chemical from a container

We have the following equation:

y = (3/10) x - 5 3/4

Then, for y = 39.1 we have:

39.1 = (3/10) x - 5 3/4

Clearing x:

(3/10) x = 39.1 + 5 3/4

(3/10) x = 44.85

x = (10/3) * (44.85)

x = 149.5 grams

Answer:

the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:

x = 149.5 grams.

3 0
3 years ago
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