An equal number of students from two Algebra 1 classes at Bozeman School were randomly selected and asked how many hours per wee
k they spend studying algebra.
The class with the largest median for hours spent studying is
-Mrs. Castro’s class
-Mr. Philippe’s class
-The medians are the same
The class with the largest range of hours spent studying is
-Mrs. Castro’s class
-Mr. Philippe’s class
-The ranges are the same
The class with the largest IQR for hours spent studying is
-Mrs. Castro’s class
-Mr. Philippe’s class
-The IQRs are the same
The class with the largest median for hours spent studying is
-Mrs. Castro’s class
-Mr. Philippe’s class
-The medians are the same
The class with the largest range of hours spent studying is
-Mrs. Castro’s class
-Mr. Philippe’s class
-The ranges are the same
The class with the largest IQR for hours spent studying is
-Mrs. Castro’s class
-Mr. Philippe’s class
-The IQRs are the same
1 answer:
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Answer:
0 ≤ Ф ≤ 4π.
Step-by-step explanation:
since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))
the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.
We take
Note that
Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.
The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.