Answer:
13.3 units (nearest tenth)
Step-by-step explanation:
Using the formula above, distance
![= \sqrt{ {[2 - ( - 1)]}^{2} + ( - 9 - 4)^{2} }](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%7B%20%7B%5B2%20-%20%28%20-%201%29%5D%7D%5E%7B2%7D%20%20%2B%20%28%20-%209%20-%204%29%5E%7B2%7D%20%7D%20)
= 13.3 units (nearest tenth)
The answer is 60, cross multiply
When reflecting across the Y axis, the Y values remain the same.
Now if you were reflecting across Y = 0, the x values would just be inverse ( opposite signs).
So this triangle if reflected across Y = 0 the new vertices would be (4,4) (2,3) and (5,2)
Now since the reflection line is y = -1, which is a one unit shift to the left of y = 0, subtract 1 unit from each X value.
The locations are now: A'(3,4), B'(1,3) and C'(4,2)
Yo sup??
we know that the sum of all the angles of a triangle is 180
therefore
11x+7x+90=180
18x=90
x=5
exterior angle formed on the ground=180-11x
=180-55
=125
Hope this helps
Answer:
28
Step-by-step explanation:
The area of a trapezoid is found by
A = 1/2 (b1+b2) *h
where b1 and b2 are the bases and h is the height
The bases are 6 and 8 and the height is 4
A = 1/2 (6+8) * 4
A = 1/2 (14)*4
=28
