Find the x and y intercepts 8x-4y= -16

1 answer:

8 0

$8x-4y=-16\\\\x-intercept\ for\ y=0:\\\\8x-4(0)=-16\\\\8x-0=-16\\\\8x=-16\qquad\text{divide both sides by 8}\\\\\boxed{x=-2\to(-2,\ 0)}\\\\y-intercept\ for\ x=0:\\\\8(0)-4y=-16\\\\0-4y=-16\\\\-4y=-16\qquad\text{divide both sides by (-4)}\\\\\boxed{y=4\to(0,\ 4)}$

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Given the relationship x2 + 3y2 =12, with y > 0 and dx, dt = 2 units/min., find the value of dy, dt at the instant y = 1 unit

matrenka [14]

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