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goldenfox [79]
3 years ago
7

Simplify this equation : xz³ × 4x³z²

Mathematics
2 answers:
Elden [556K]3 years ago
5 0
Answer is 4x^4 x z^5
Virty [35]3 years ago
5 0

Answer:

4x^4z^5

Step-by-step explanation:

xz^3 * 4x^3z^2

As we are multiplying, we use the addition power law to simplify the powers of each term:

n^a * n^b = n^{a+b}

4*x^{1+3}*z^{3+2}=4x^4z^5

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Help asap pls -=-=-=-=--------------
bixtya [17]

Answer:

-1/3

Step-by-step explanation:

at x=0 y= 5

at x=3 y= 4

y=ax+b

b= 5

4=3x+5

3x= -1

x= -1/3

y =  -  \frac{x}{3}  + 5

5 0
3 years ago
Someone please tell me how to solve this
rewona [7]
The answer will be 21u^6v^8
6 0
3 years ago
Round to the nearest hundredth 5/8
Solnce55 [7]
Eighths and their multiples are common fractions which I recommend memorizing, but to actually solve this, you use the literal meaning of a fraction and divide 5 by 8. See the long-division below (it was surprisingly difficult to type, so I hope it helps!).

To round 0.625 to the nearest hundredth, we go to the second decimal place, which is 5, so we round up to 0.63.

3 0
3 years ago
R=x^2/y <br> x=3.8 times 10^5 <br> y=5.9 times 10^4 <br> work out the value of r
Zinaida [17]

Answer:

  2.4×10^6

Step-by-step explanation:

Put the numbers where the variables are and do the arithmetic. You can enter the numbers in scientific notation into your (scientific) calculator and have it show you the result in the same format.

  r = (3.8×10^5)^2/(5.9×10^4) . . . . . denominator parentheses are required

Please note that in the above expression, parentheses are required around the denominator number. This is because it is a product of two numbers. In your pocket calculator or spreadsheet, you can enter that value as a single number (not a product). Parentheses are not required when you can do that.

  r = (3.8²/5.9)×10^(5·2-4) ≈ 2.4×10^6

___

The "exact" value is a repeating decimal with a long repeat. We have rounded to 2 significant digits here because the input numbers have that number of significant digits.

7 0
2 years ago
Given that the quadratic equation has equal roots (k^2-1)x^2-2kx-3k-1=0
Alik [6]

Answer:

(See explanation for further details)

Step-by-step explanation:

The real expression is:

(k^{2}-1)\cdot x{{2} - 2\cdot k \cdot x - 3\cdot k + 1 = 0

The general equation for the second-order polynomial is:

x = \frac{2\cdot k \pm \sqrt{4\cdot k^{2}-4\cdot (k^{2}-1)\cdot (-3\cdot k + 1)}}{k^{2}-1}

This condition must be observed for the case of a quadratic equation with equal roots:

4\cdot k^{2} - 4\cdot (k^{2}-1)\cdot (-3\cdot k + 1) = 0

k^{2} + (k^{2}-1)\cdot (3\cdot k + 1) = 0

k^{2} + 3\cdot k^{3} - 3\cdot k - k^{2}-1 = 0

3\cdot k^{3} - 3\cdot k - 1 = 0

7 0
3 years ago
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