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Whitepunk [10]
3 years ago
8

---------------------------------------------------------------------------------------- 10x10?

Mathematics
2 answers:
statuscvo [17]3 years ago
4 0
100
------------------------------------------------------------------------
a_sh-v [17]3 years ago
3 0
10x10=100
------------------------------------ :))
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4.) The time X (minutes) for a lab assistant to prepare the equipment for a certain experiment is believed to have a uniform dis
Jet001 [13]

Answer:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

Step-by-step explanation:

For this case we define the following random variable X= (minutes) for a lab assistant to prepare the equipment for a certain experiment , and the distribution for X is given by:

X \sim Unif (a= 20, b =50)

The cumulative distribution function is given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

The expected value is given by:

E(X) = \frac{a+b}{2} = \frac{20+50}{2}=35

And we want to find the following probability:

P(35-2 < X 35+2) = P(33< X< 37)

And we can find this probability on this way:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

And using the cumulative distribution function we got:

P(35-2 < X 35+2) = P(33< X< 37)= P(X

The probability that preparation is within 2 minutes of the mean time is 0.134

8 0
3 years ago
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