Answer:
6850 & 650
Step-by-step explanation:
The question is partly incomplete as it didn't state the cost of ticket sold. Also, it didn't state the total number of tickets sold. But, assuming that the tickets sold were $15 and $25 tickets, and the total number of tickets sold was 7500, then we say that
Let x = the number of $15 tickets sold
Let y = the number of $25 tickets sold
x + y = 7500 y = 7500 - x
15x + 25y = 119000
15x + 25(7500-x) = 119000
15x + 187500 - 25x = 119000
-10x = -68500
x = 68500 / 10
x = 6850 tickets at $15 each
Remember from the first calculation, we said x + y = 7500, then
y = 7500 - 6850
y = 650 tickets at $25 each
All you have to do is substitute the values I assumed for your given value. Thanks
Let p = pictures only
let f = pictures with frames
p + f = 100
5p + 10f = 875
Solve for one variable in the first equation then plug into the second
p = 100 - f
5(100 - f) + 10f = 875
500 - 5f + 10f = 875
500 + 5f = 875
5f = 375
f = 75
75 pictures with frames were sold
The answer would be as follows:
(s+t)(x) = s(x)+t(x)
So:
(s+t)(x) = (x+6)+(3x+2)
Simplify:
(s+t)(x) = 4x+8
