Explanation:
The human body has three primary lines of defense to fight against foreign invaders, including viruses, bacteria, and fungi. The immune system's three lines of defense include physical and chemical barriers, non-specific innate responses, and specific adaptive responses.
<span>The Quebec Blackout was different, because this one was caused by a solar storm.</span>
Answer:
c) probably a mixture of DNA and RNA.
Explanation:
DNA and RNA are the two types of nucleic acids present in cells. DNA or deoxyribose nucleic acid is composed of four type of bases ( adenine, thymine, guanine and cytosine ), deoxyribose sugar and phosphate group. RNA or ribose nucleic acid is composed of four types of bases ( adenine, uracil, guanine and cytosine), ribose sugar and phosphate group.
Here, the sample had adenine which could be either from DNA or RNA. Thymine is from DNA. Ribose sugar is from RNA and uracil is from RNA. Hence, the sample has a mixture of DNA and RNA.
Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
