Let be x the number;
We have (1/3)*x + x = 28 ;
x/3 + 3x/3 = 84/3 ;
4x = 84;
x = 84 ÷ 4 ;
x = 21.
Let the length of equal sides be x cm. Perimeter = x cm + x cm + Base = 4 2/15 cm 2x + 4/3 = 62/15 On transposing 4/3 to R.H.S, we obtain 2x = 62/15 - 4/3 2x = 62 - 4 x 5/15 = 62 - 20/15 2x = 42/15 On dividing both sides by 2, we obtain 2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5 Therefore, the length of equal sides is 1 2/5 c m.
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Answer:
(c) Both equations have the same potential solutions, but equation A might have extraneous solutions.
Step-by-step explanation:
The general approach to solving an equation like either of these is to raise both sides of the equation to a power that will remove the radical. In both cases, the result is a quadratic with roots of x=-4 and x=2.
Of these two potential solutions, x = -4 is an extraneous solution for equation A. Both values of x are solutions for equation B. An appropriate description is ...
Both equations have the same potential solutions, but equation A might have extraneous solutions.
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<em>Additional comment</em>
The attached graph shows the equations cast into the form f(x) = 0, so x-intercepts are the solutions to the equation. The radical versions of the equations have only x-intercepts that are actual solutions. The version with the radicals removed is a parabola with two solutions (orange). Only one of those matches the solution to equation A (red). Both match the solutions of equation B (purple).
You can't solve for the zeros by factoring because the function is not factorable.
I'll show you what happens:
f(x) = 6x^2 + 6x + 12
To solve for the zeros (when f(x)=0), set f(x) equal to 0.
0 = 6x^2 + 6x + 12
First you can factor out a 6.
0 = 6(x^2 + x + 2)
Divide by 6.
0 = x^2 + x + 2
Now you need two integers that add up to the coefficient of x (1) and multiply to the product of the last term and the coefficient of x^2. This number is 2.
No two integers add up to 1 and multiply to 2.
Answer:
B) m=15.50h
Step-by-step explanation:
77.50 ÷ 5 = 15.50
279 ÷ 18 = 15.50
Randy makes $15.50 per hour.