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3 years ago

12. How much do 21 bushels of sweet

Mathematics

1 answer:

lesantik [10]3 years ago

8 0

Answer:

21 bushels of sweet corm weight 735 pounds.

Step-by-step explanation:

Given:

Weight of 21 bushels of sweet corn is obtained by multiplying the unit weight to the number of bushels required.

Unit weight of sweet corn is the weight of 1 bushel of sweet corn.

Weight of 1 bushel of sweet corn = 35 pounds

So, weight of 21 bushels of sweet corns = $35\times 21=735$ pounds.

Therefore, 21 bushels of sweet corn weigh 735 pounds.

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Cot^2x csc^2x + 2 csc^2x –cot^2 = 2

kow [346]

Answer:

x = π/2 + πk

Step-by-step explanation:

cot² x csc² x + 2 csc² x − cot² x = 2

Multiply both sides by sin² x:

cot² x + 2 − cos² x = 2 sin² x

Add cos² x to both sides:

cot² x + 2 = 2 sin² x + cos² x

Pythagorean identity:

cot² x + 2 = sin² x + 1

Subtract 1 from both sides:

cot² x + 1 = sin² x

Pythagorean identity:

csc² x = sin² x

Multiply both sides by sin² x:

1 = sin⁴ x

Take the fourth root:

sin x = ±1

Solve for x:

x = π/2 + 2πk, 3π/2 + 2πk

Which simplifies to:

x = π/2 + πk

4 0

4 years ago

Is the point (1,5) a solution to the equation below?

allochka39001 [22]

Answer:

A. No

Step-by-step explanation:

y = 2x + 4

(5) = 2(1) + 4

5 = 2 + 4

5 = 6 (false statement)

7 0

3 years ago

A triangle has side lengths measuring 2x + 2 ft x + 3 ft, and

Marta_Voda [28]

Answer:

$3x+5 < n < x-1$

Step-by-step explanation:

we know that

The <u><em>Triangle Inequality Theorem</em></u> states that the sum of any 2 sides of a triangle must be greater than the measure of the third side

Applying the Triangle Inequality Theorem

1) $(2x+2)+(x+3) > n$

solve for n

$3x+5> n$

Rewrite

$n$

2) $(x+3)+n> 2x+2$

$n> x-1$

therefore

$3x+5 < n < x-1$

5 0

3 years ago

A supermarket is selling two types of candies, orange slices and strawberry leaves. The orange slices cost $1.27 per pound and

garik1379 [7]

The question here has wrong numbers. Here is the correct question:

A supermarket is selling 2 types of candies, orange slices and strawberry leaves. The orange slices cost $1.27 per pound and the strawberry leaves cost $1.77 per pound. How many pounds of each should be mixed to get a 13-pound mixture that sells for $19.01?

Answer:

8 pounds of orange slices and 5 pounds of strawberry leaves

Step-by-step explanation:

This question is related to simple algebra

Let x represent orange slices weight

Let y represent strawberry leaves weight

The sum of the weights of x and y will be 13 pounds

So first equation will be x + y = 13

The total cost will be $19.01

So the second equation will be

1.27x + 1.77y = 19.01

Using first equation

x + y = 13

x = 13 – y

Substituting this in the second equation

1.27 (13 - y) + 1.77y = 19.01

16.51 – 1.27y + 1.77y = 19.01

16.51 + 0.5y = 19.01

y = 5

Using this value of y to find x

x = 13 – y

x = 13 – 5

x = 8

So 8 pounds of orange slices and 5 pounds of strawberry leaves

3 0

3 years ago

Read 2 more answers

There are 90 apples shared equally among 6 baskets. Hun buys 1 basket of apples. He uses the apples to make 3 pies. Each pie has

tamaranim1 [39]

Answer:

To find the number of apples per basket we divide 90 by 6 to get 15. We know that he buys 15 apples. We now have to divide by 3 to get the number of apples per pie, because we know he used all 15 apples. The answer is 15/3 or 5 apples per pie. 5 apples

6 0

3 years ago

Read 2 more answers