Answer:
30
Step-by-step explanation:
okay. the point has an x and y value. place them into the equation.
1=m(1)+b
m=slope, and theequation tells you that slope is 7.
1=7(1)+b
now you need to figure out what b is.
1=7(1)+b
^
1= 7 +b
-7 -7
---------------
-6=B
b is 6. now place it into the equation, replacing the x and y values back.
y=7x-6.
write 7 and 6 in the boxes (the negative for the six has already been provided)
Answer:
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<h2>Given</h2>
<h3>Line 1</h3>
<h3>Line 2</h3>
- Passing through the points (4, 3) and (5, - 3)
<h2>To find</h2>
- The value of k, if the lines are perpendicular
<h2>Solution</h2>
We know the perpendicular lines have opposite reciprocal slopes, that is the product of their slopes is - 1.
Find the slope of line 1 by converting the equation into slope-intercept from standard form:
<u><em>Info:</em></u>
- <em>standard form is ⇒ ax + by + c = 0, </em>
- <em>slope - intercept form is ⇒ y = mx + b, where m is the slope</em>
- 3x - ky + 7 = 0
- ky = 3x + 7
- y = (3/k)x + 7/k
Its slope is 3/k.
Find the slope of line 2, using the slope formula:
- m = (y₂ - y₁)/(x₂ - x₁) = (-3 - 3)/(5 - 4) = - 6/1 = - 6
We have both the slopes now. Find their product:
- (3/k)*(- 6) = - 1
- - 18/k = - 1
- k = 18
So when k is 18, the lines are perpendicular.
9514 1404 393
Answer:
3, 0, 2, -2
Step-by-step explanation:
Put x=2 into each equation and solve for y.
<u>2 + y = 5</u>
y = 5 -2
y = 3
<u>3x +2y = 6</u>
3·2 +2y = 6
2y = 6 -6 = 0
y = 0
<u>2x +y = 6</u>
2·2 +y = 6
y = 6 -4
y = 2
<u>5x +3y = 4</u>
5·2 +3y = 4
3y = 4 -10 = -6
y = -2
