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3 years ago

Find the value of y if the value of x is 2 for each equation and match it with the appropriate result.

Mathematics

1 answer:

Xelga [282]3 years ago

4 0

9514 1404 393

Answer:

3, 0, 2, -2

Step-by-step explanation:

Put x=2 into each equation and solve for y.

2 + y = 5

y = 5 -2

y = 3

3x +2y = 6

3·2 +2y = 6

2y = 6 -6 = 0

y = 0

2x +y = 6

2·2 +y = 6

y = 6 -4

y = 2

5x +3y = 4

5·2 +3y = 4

3y = 4 -10 = -6

y = -2

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71.40 divided by 6

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3 years ago

What is the smaller of the numbers 1 and -10/3

antiseptic1488 [7]

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2 years ago

Read 2 more answers

Please help me fill in the blanks :)

guapka [62]

Answer:

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Step-by-step explanation:

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3 years ago

Find the center of mass of a thin plate of constant density covering the given region bounded by lines thru the following points

goldenfox [79]

Answer:

center of mass = ( 1 ,2 )

Step-by-step explanation:

attached below is the detailed solution of the problem

first we have to determine the value of m

M = ∫∫ dA

= 6

Mx = 12

attached solution below

My = 6

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x , y

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3 years ago

Consider the function f(x) = √5x + 15 for the domain [-3, ∞).Find f-¹(x), where f-1 is the inverse of f.Also state the domain of

Ymorist [56]

Answer: We have to find the inverse function of the following:

$f(x)=\sqrt{5x+15}\rightarrow[-3,\infty)\Rightarrow(1)$

The Inverse of the (1) is as follows:

$\begin{gathered} f(x)=y=\sqrt{5x+15} \\ \\ \text{ Switch: }x\text{ and }y\text{ and solve for }y(x)\text{ } \\ \\ \\ y=\sqrt{5x+15}\rightarrow x=\sqrt{5y+15} \\ \\ \\ x^2=5y+15 \\ \\ \\ x^2-15=5y \\ \\ \\ y=\frac{x^2}{5}-\frac{15}{5} \\ \\ \\ \\ y=f^{-1}(x)=\frac{x^2}{5}-3 \\ \\ \\ f^{-1}(x)=\frac{x^{2}}{5}-3 \end{gathered}$

The domain of the inverse function is:

$x\in(-\infty,+\infty)$

3 0

1 year ago