Answer:
that equation isn't factorable
Answer:
depends on what the radius is
:)
Step-by-step explanation:
Answer:
Once the equation is in standard form, factor the quadratic expression. 2x2 + 7x + 3 = 0 (2x + 1)(x + 3) = 0. Using the Zero Product Property set ...
2x2 + 7x = -3
2x2 + 7x + 3 = 0
Once the equation is in standard form, factor the quadratic expression.
2x2 + 7x + 3 = 0
(2x + 1)(x + 3) = 0
Using the Zero Product Property set each factor equal to 0 and solve for x.
2x + 1 = 0
2x + 1 - 1 = 0 - 1 x + 3 = 0
2x = -1 x + 3 - 3 = 0 - 3
2x 2 = -1 2 x = -3
x = -1 2
The solutions to the equation are -1 2 and -3.
Answer: Yes, No
Step-by-step explanation:
1st table is linear because the slope is always constant.
Second is not linear, but rather exponential.
Arc length = rθ [r = radius of the circle, θ = central angle in radians] ⇒
2π = 8*θ ⇒ θ = 2π/8 = π/4
