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Ber [7]
3 years ago
14

Hope u help me pls I love u

Mathematics
1 answer:
QveST [7]3 years ago
8 0

Answer:c= a +b

Step-by-step explanation:

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a dining room table and chairs are priced at $869. Mrs. Brown has a coupon for $75 off the original price. If the tax on the sal
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Ellie's Bakery is having a grand opening sale. All pastries are being discounted by 25%. Let x represent the regular price of an
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a) The expression to find the sale price of pastry =  0.75 x

b)  The regular price of the pastry bought by Kimberly = $2.70

Step-by-step explanation:

Step 1 :

Let x be the regular price of the pastry in the bakery

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<u>To find the regular price</u>

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Regular price of the pastry bought by Kimberly = $2.70

Step 3 :

Answer :

a) The expression to find the sale price of pastry =  0.75 x

b) The regular price of the pastry bought by Kimberly = $2.70

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3 years ago
Am i correct? calculus
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Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

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\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y&#10;\\\\\\&#10;\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}&#10;\\\\\\&#10;\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\&#10;-------------------------------\\\\&#10;

\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}&#10;\\\\\\&#10;\cfrac{d\theta }{dt}=\cfrac{11}{75}

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3 years ago
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jeka94

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3

*if you ever need to do more math like this, I suggest using desmos :)

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