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lara [203]
3 years ago
10

This is a double question. Part 1: 5(2x - 4) = 30. Solve for x Part 2: 5x + 3 - x + 2 = 41. Solve for x. I will mark Brainliest

to whoever solves both parts as well as explains it.
Mathematics
2 answers:
SOVA2 [1]3 years ago
4 0
PART 1:
5(2x-4)=30
Multiply both 2x and -4 by 5

10x-20=30
Then add 20 to cancel it out, but once u do something to that side u must do it to the other side. So add 20 to 30 which is 50.

10x=50

10x/10= 50/10
Divide both side by 10

X=5



PART 2:
5x + 3 - x + 2 = 41

4x + 5 = 41
Combine the like terms

4x=36
Then subtract 5 from both sides to cancel to get 4x by itself

4x/4=36/4
Then divide both sides by 4

X=9
Ainat [17]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

Part 1: 5(2x - 4) = 30.

Distribute

10x -20 = 30

Add 20 to each side

10x-20+20 =30+20

10x = 50

Divide by 10

10x/10 = 50/10

x =5

Part 2: 5x + 3 - x + 2 = 41

Combine like terms

4x +5 = 41

Subtract 5 from each side

4x+5-5 = 41-5

4x = 36

Divide by 4

4x/4 = 36/4

x = 9

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Step-by-step explanation:

The angle with vertex T is called an "inscribed angle." It intercepts arc SU. The relationship you are asked to remember is that the measure of the inscribed angle (T) is half the measure of the arc SU.

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Using these two relationships together, we realize angle V is twice the measure of angle T:

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  18x +12° = 2(18x -57°) . . . . . . relationship between the marked angles

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<em>Additional comment</em>

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<em>Alternate solution</em>:

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