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WINSTONCH [101]
2 years ago
8

Order of operations, step by step 56-12 / 6+4

Mathematics
1 answer:
icang [17]2 years ago
7 0

Answer:

58

Step-by-step explanation:

<u>Order of operations:</u>

  • Parentheses
  • Exponents
  • Multiplication-Division
  • Addition-Subtraction

<u>Solve:</u>

56-12 / 6+4

56 - (12/6) +4  { No Multiplication but do have Division} (12/6 = 2)

56 - 2 + 4 {Subtraction ⇒ 56-2 = 54}

54 + 4 { Addition ⇒ 54 + 4 = 58}

<u>Answer = </u>58

[RevyBreeze]

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Can someone please professionally explain the math equations below. (Not just answer the question)
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Step-by-step explanation:

We will solve this system of equations using two methods: elimination and substitution.

Method 1: Elimination

2x - y = -8. #1

-5x + y = 26. #2

Note that by adding these two equations, the y-variable is eliminated (thus the name) and you're only left with an equation with one variable. So upon adding, we get

-3x = 18 or x = -6

Using this value for x, put this back in either one of the equations. Let's use the 2nd one.

-5(-6) + y = 26

--> 30 + y = 26

Moving 30 to the right side, we get y = -4.

Method 2: Substitution

This is done by isolating one variable to the left side in one equation and then using it on the other equation. Let's take equation #2 and put the y-variable on the left side and you should get

y = 5x + 26

Now use this equation and plug it into the y in equation #1:

2x - (5x + 26) = -8

--> 2x - 5x - 26 = -8

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Use this value for x into either one of the equations. Let's use equation #1 this time.

2(-6) - y = -8

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Notice that using either method will give you the same result, as one might expect.

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Answer:

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Step-by-step explanation:

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