Da answer to this question is 43
Answer:
a) probability that neither is Tay-Sachs carrier is 0.9298
b) the probability that both are carriers is 0.001276
Step-by-step explanation:
Given that;
1 in 28 people of Ashkenazi jewish descent are Tay-Sachs carrier.
so P(Carrier) = 1/28 =
also P( Not a carrier) = 1 - 1/28 = 0.9643
Now After Sampling 1 man and 1 woman from the population;
a)
the probability neither is Tay-Sachs carrier
P( Neither is a Carrier) = 27/28 × 27/28 = 0.9298
Therefore probability that neither is Tay-Sachs carrier is 0.9298
b)
the probability both are carriers
P( Both are Carriers) = 1/28 × 1/28 = 0.001276
Therefore the probability that both are carriers is 0.001276
<span>(2.2 × 1012) + (1.7 × 109) = 2411.7</span>
Answer:
6
Step-by-step explanation:
Answer:
y
=
x
3
−
4
x
y
=
x
2
+
4
y
=
3
x
−
4
Step-by-step explanation: