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3 years ago

Which factor causes the shapes of saturated and unsaturated fatty acids to differ?

2 answers:

kondor19780726 [428]3 years ago

6 0

Whether or not the fatty acid has double or single covalent bonds

a fatty acid is saturated when only single bonds to H hold it together

a fatty acid is unsaturated when a double bond helps hold it together, this type of fatty acid becomes bent as a result

Romashka-Z-Leto [24]3 years ago

3 0

Answer:

The correct answer will be- double bond in fatty acids.

Explanation:

Two types of fatty acids are present in nature: saturated and unsaturated fatty acids.

The saturated fatty acid is a molecule which gets saturated with the maximum number of hydrogen atoms the carbon skeleton can have whereas unsaturated fatty acid exhibit a double bond in their structure which cause the bending of the carbon skeleton due to different bending angle.

The double bond provides different shape to the unsaturated fatty acid which is absent in the saturated fatty acids.

Thus, the double bond in a fatty acid is the correct answer.

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3 years ago

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Answer:

a) $0.316$

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d) $0.0117$

e) $0.0039$

Explanation:

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$\frac{3}{4} * \frac{3}{4} * \frac{3}{4} * \frac{3}{4} \\= \frac{81}{256} \\= 0.316$

b) Probability of 3 blue and 1 white

$\frac{3}{4} * \frac{3}{4}* \frac{3}{4}* \frac{1}{4}\\= \frac{27}{256} \\= 0.105$

c) Probability of 2 blue and 2 white

$\frac{3}{4} * \frac{3}{4}* \frac{1}{4}*\frac{1}{4}\\= 0.035$

d) Probability of 1 blue and 3 white

$\frac{3}{4} * \frac{1}{4} * \frac{1}{4}* \frac{1}{4}\\= \frac{3}{256} \\= 0.0117$

e) Probability of all white

$\frac{1}{4} * \frac{1}{4} * \frac{1}{4} * \frac{1}{4} \\= \frac{1}{256} \\= 0.0039$

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3 years ago