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zaharov [31]
3 years ago
10

PLEASE HELP !! ILL GIVE BRAINLIEST !! 100 POINTS

Mathematics
2 answers:
WITCHER [35]3 years ago
3 0

Answer:

7 is the answer

Step-by-step explanation:

63 ÷ 7 = 7 therefore it's 7

DiKsa [7]3 years ago
3 0

Answer: M=9. Divide 63/7

Step-by-step explanation:

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What is the output of the function f(p) = 3p – 2 when the input is 2?
vovikov84 [41]
Just plug in 2 for p. 3*2 - 2 = 6-2 = 4
4 0
4 years ago
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Please find the general limit of the following function:
valentinak56 [21]

Answer:

The general limit exists at <em>x</em> = 9 and is equal to 300.

Step-by-step explanation:

We want to find the general limit of the function:

\displaystyle \lim_{x \to 9}(x^2+2^7+(9.1\times 10))

By definition, a general limit exists at a point if the two one-sided limits exist and are equivalent to each other.

So, let's find each one-sided limit: the left-hand side and the right-hand side.

The left-hand limit is given by:

<h3>\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))</h3>

Since the given function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

300

Therefore:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1 \times 10))=300

The right-hand limit is given by:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))

Again, since the function is a polynomial, we can use direct substitution. This yields:

=(9)^2+2^7+(9.1\times 10)

Evaluate:

=300

Therefore:

\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Thus, we can see that:

\displaystyle \lim_{x \to 9^-}(x^2+2^7+(9.1\times 10))=\displaystyle \lim_{x \to 9^+}(x^2+2^7+(9.1\times 10))=300

Since the two-sided limits exist and are equivalent, the general limit of the function does exist at <em>x</em> = 9 and is equal to 300.

8 0
3 years ago
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Is my answer correct?
nexus9112 [7]

Answer:

yes

Step-by-step explanation:

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What is the equation of the graph?<br><br> y = 4x<br> y = 1/4x<br> y = -1/4x<br> y = -4x
Hatshy [7]
Y=1/4x is the correct answer
8 0
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Car A began a journey from a point at 9 am, traveling at 30 mph. At 10 am car B started traveling from the same point at 40 mph
Natasha2012 [34]
Let after t hours the distances D1<span> traveled by car A</span>

=> D1<span> = 30 t</span>

Car B starts at 10 am and will, therefore, have spent one hour less than car A when it passes it.

After (t - 1) hours, distance D2<span> traveled by car B </span>

=> D2<span> = 40 (t - 1)</span>

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=> 30 t = 40 (t - 1)

Solve the equation for t,

=> 30 t = 40t - 40

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=><span> Car B passes car A at = 9 + 4 = 13 pm.</span>
7 0
3 years ago
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