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mariarad [96]
3 years ago
8

A right cylinder has the radius of 3.5cm and the height of 11cm if i place 3 ice cube with edge length of 2cm in the glass what

volume of juice will i add to fill the glass to the top?
Mathematics
1 answer:
Brrunno [24]3 years ago
4 0

Answer:

Volume of cylinder =

\pi  \times r {}^{2}  \times h

\pi \times 3.5 {}^{2}  \times 11 = 423cm {}^{3}

Volume of 1 ice cube = 2*2*2= 8cm3

Volume of 3 ice cubes= 3*8= 24cm3

Volume of juice added = 423-24 = 399 cm3

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What is the area of the triangle? On a coordinate plane, a triangle has a base of 8 units and a height of 6 units. 24 square uni
LekaFEV [45]

Answer:

24

Step-by-step explanation:

8*6=48/2=24

6 0
3 years ago
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If y=24 when x=21, find y when x is 18
ludmilkaskok [199]

Answer:20.571

Step-by-step explanation:

x:y = 21: 24=7:8

8x=7y

y=8x/7

When x=18

y=8*18/7

y=20.571

5 0
3 years ago
Plzzz help for brianly
Temka [501]

Answer:

Add up the area of all the sides

Step-by-step explanation:

Surface area is the shell of a 3d shape, not the volume so you add the outside of the shape.

Hope this helps! :)

4 0
3 years ago
For what value of x is (2x^2+8x)/(x+4)(x^2-9) undefined?
irakobra [83]

Answer:

The value at x =3 is undefined for the given expression

Step-by-step explanation:

Given expression is \frac{2x^2+8x}{(x+4)(x^2-9)}

To find for what value of x is undefined in the given expression :

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x(x+4)}{(x+4)(x^2-9)}

=\frac{2x}{x^2-9}

\frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{2x}{x^2-9}

If we put x=3 in the above expression we get

\frac{2x}{x^2-9)}=\frac{2(3)}{3^2-9}

=\frac{6}{9-9}

=\frac{6}{0}

Therefore \frac{2x^2+8x}{(x+4)(x^2-9)}=\frac{6}{0}

The value at x =3 is undefined for the given expression

7 0
3 years ago
Please help i dont understand what its asking
Arisa [49]

Multiply both the numerator and denominator by 2+\sqrt3, which is called the "conjugate" of 2-\sqrt3:

\dfrac{5+\sqrt3}{2-\sqrt3}\cdot\dfrac{2+\sqrt3}{2+\sqrt3}

Why do we pick this number? Recall the difference of squares factorization:

a^2-b^2=(a-b)(a+b)

Now replace a=2 and b=\sqrt3. Then

(2-\sqrt3)(2+\sqrt3)=2^2-(\sqrt3)^2=4-3=1

So in your fraction, you end up with

\dfrac{5+\sqrt3}{2-\sqrt3}=\dfrac{(5+\sqrt3)(2+\sqrt3)}1=(5+\sqrt3)(2+\sqrt3)

Finally, just expand the product.

(5+\sqrt3)(2+\sqrt3)=10+7\sqrt3+(\sqrt3)^2=\boxed{13+7\sqrt3}

7 0
3 years ago
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