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mariarad [96]
3 years ago
8

A right cylinder has the radius of 3.5cm and the height of 11cm if i place 3 ice cube with edge length of 2cm in the glass what

volume of juice will i add to fill the glass to the top?
Mathematics
1 answer:
Brrunno [24]3 years ago
4 0

Answer:

Volume of cylinder =

\pi  \times r {}^{2}  \times h

\pi \times 3.5 {}^{2}  \times 11 = 423cm {}^{3}

Volume of 1 ice cube = 2*2*2= 8cm3

Volume of 3 ice cubes= 3*8= 24cm3

Volume of juice added = 423-24 = 399 cm3

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: Find the slope between the two points given. Then, use the slope and point ONE to write the equation of the line in Point-Slop
Ierofanga [76]

Answer:

           slope:      \bold{m=3}

      equation:     \bold{y-2=3(x-1)}

Step-by-step explanation:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(1,\,2)\ \implies\ x_1=1\,,\ y_1=2\\(0,\,-1)\ \implies\ x_2=0\,,\ y_2=-1\\\\m=\dfrac{-1-2}{0-1}=\dfrac{-3}{-1}=3

y-y_1=m(x-x_1)      - point-slope form of Equation of the Line

x_1=1\,,\ y_1=2\,,\ m=3\\\\equation:\\{}\qquad\qquad y-2=3(x-1)

8 0
3 years ago
Prove that:- (1-sinA)(1+sinA)÷(1+cosA)(1-cosA)=cot^2A​
astraxan [27]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

sin²x + cos²x = 1 , then

sin²x = 1 - cos²x and cos²x = 1 - sin²x

Consider the left side

\frac{(1-sinA)(1 + sinA)}{(1+cosA)(1-cosA)} ← expand numerator/denominator using FOIL

= \frac{1-sin^2A}{1-cos^2A}

= \frac{1-(1-cos^2A)}{1-(1-sin^2A)}

= \frac{1-1+cos^2A}{1-1+sin^2A}

= \frac{cos^2A}{sin^2A}

= cot²A = right side , thus proven

6 0
3 years ago
(4x - 3) × (x + 2)=0
matrenka [14]

Hi,

AxB = 0 means A=0. or B=0

so 2 solutions :

4x-3= 0

4x=3

x = 3/4

and x+2 = 0.

x= -2

solutions are : -2 +and 3/4

7 0
3 years ago
Read 2 more answers
Multiply (x + 1)³
nlexa [21]

Answer:

x³+3x²+3x+1

Step-by-step explanation:

=(x+1)(x+1)(x+1)

=(x+1)(x²+x+x+1)

=(x+1)(x²+2x+1)

=(x³+2x²+x+x²+2x+1)

=x³+3x²+3x+1

4 0
2 years ago
Read 2 more answers
Mr. Thomas drove 75 miles in May. He drove 6 times as many miles in July as he did in May. He
harkovskaia [24]

Answer:

1800 miles

Step-by-step explanation:

No. of miles driven by Mr. Thomas in May = 75

It is given that miles driven in July is 6 times of miles driven by Mr. Thomas in May(75 miles).

Thus

No. of miles driven by Mr. Thomas in July = 6 * No. of miles driven by Mr. Thomas in May   = 6*75 = 450 miles.

__________________________________________________

Another condition given   that miles driven in June is 4 times of miles driven by Mr. Thomas in July(450miles as calculated above).

Thus

No. of miles driven by Mr. Thomas in June = 4 * No. of miles driven by Mr. Thomas in July   = 4* 450 miles = 1800 miles.

No. of miles driven by Mr. Thomas in June is 1800 miles.

8 0
3 years ago
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