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enot [183]
3 years ago
7

What is the range of the function f(x)=3x^2+6x-8

Mathematics
2 answers:
kvv77 [185]3 years ago
6 0

Answer:

The range is [-11, ∞).

Step-by-step explanation:

f(x)=3x^2+6x-8

This is a parabola which opens upwards.

Convert to vertex form:

= 3(x^2 + 2x) - 8

= 3 [ (x + 1)^2 - 1] - 8

= 3(x + 1)^2 - 3 - 8

=  3(x + 1)^2 - 11.

The minimum value is -11 so the range is [-11, ∞).

astraxan [27]3 years ago
5 0

Answer:

[-11,∞),{yiy≥-11}

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As the question is not complete, Here is the complete question.

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