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Simora [160]
3 years ago
9

If f(x)=3x+2 and g(x)=x^2-3x-4, what is (g0f)(5)

Mathematics
1 answer:
andre [41]3 years ago
8 0

\bf \begin{cases} f(x)=3x+2\\ g(x)=x^2-3x-4\\[-0.5em] \hrulefill\\ (g\circ f)(5)=g(~~f(5)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(5)=3(5)+2\implies f(5)=17 \\\\[-0.35em] ~\dotfill\\\\ g(~~f(5)~~)\implies g(~~17~~)=(17)^2-3(17)-4\implies g(17)=289-58-4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{(g\circ f)(5)}{g(17)=227}~\hfill

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If the discriminant of a quadratic equation is equal to -8, which statement describes the roots?
Dovator [93]

Keywords

quadratic equation, discriminant, complex roots, real roots

we know that

The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form  ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}

where

The <u>discriminant</u> of the <u>quadratic equation</u>  is equal to

b^{2}-4ac

if  (b^{2}-4ac)> 0 ----> the <u>quadratic equation</u> has two <u>real roots</u>

if  (b^{2}-4ac)=0 ----> the <u>quadratic equation</u> has one <u>real root</u>

if  (b^{2}-4ac)< 0 ----> the <u>quadratic equation</u> has two <u>complex roots</u>

in this problem we have that

the <u>discriminant</u> is equal to -8

so

the <u>quadratic equation</u> has two <u>complex roots</u>

therefore

the answer is the option A

There are two complex roots

5 0
3 years ago
Read 2 more answers
??????????????????????
siniylev [52]
The correct answer a 40
5 0
3 years ago
A club is planning on printing custom t-shirts for the 2013 academic year.
lions [1.4K]
 50+ 7.99 x =y
50+ 7.99 (40)= y
50+319.60= y
369.60=y

50+ 7.99 x =y
50 + 7.99 (50)
50+ 399.50=449.50
6.99(30)=209.70
449.50 + 209.70 =659.2 

7 0
3 years ago
Read 2 more answers
What is the perimeter of a square whose diagonal is 3 square root 2? Show all work on how you got your answer
Alika [10]

Answer:

12

Step-by-step explanation:

Given: Diagonal of square= 3\sqrt{2}

To find the perimeter of square, we need to find the length of sides of square.

∴ Using the formula of diagonal to find side of square.

Formula; Diagonal= s\sqrt{2}

Where, s is side of square.

⇒ 3\sqrt{2} = s\sqrt{2}

Dividing both side by √2

⇒s= \frac{3\sqrt{2} }{\sqrt{2} }

∴s= 3

Hence, Length of side of square is 3.

Now, finding the perimeter of square.

Formula; Perimeter= 4s

⇒Perimeter= 4\times 3

∴ Perimeter= 12

Hence, Perimeter of square is 12.

6 0
4 years ago
Help please I’m not sure how to do this
joja [24]

the answer for this would be the last one. two rays that meet at a end point.

hope this helps!

3 0
3 years ago
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