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Simora [160]
2 years ago
9

If f(x)=3x+2 and g(x)=x^2-3x-4, what is (g0f)(5)

Mathematics
1 answer:
andre [41]2 years ago
8 0

\bf \begin{cases} f(x)=3x+2\\ g(x)=x^2-3x-4\\[-0.5em] \hrulefill\\ (g\circ f)(5)=g(~~f(5)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(5)=3(5)+2\implies f(5)=17 \\\\[-0.35em] ~\dotfill\\\\ g(~~f(5)~~)\implies g(~~17~~)=(17)^2-3(17)-4\implies g(17)=289-58-4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{(g\circ f)(5)}{g(17)=227}~\hfill

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Write the equation for the perpendicular bisector of the given line segment.
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Answer:

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find the equation of the segment  two point (-5,5) and (-2,-4)

m=y2-y1/x2-x1 =5-(-4)/-5-(-2) =9/-3 = -3

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Divide the following polynomials. Write the answer in descending powers of a.
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At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

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3 years ago
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