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Simora [160]
2 years ago
9

If f(x)=3x+2 and g(x)=x^2-3x-4, what is (g0f)(5)

Mathematics
1 answer:
andre [41]2 years ago
8 0

\bf \begin{cases} f(x)=3x+2\\ g(x)=x^2-3x-4\\[-0.5em] \hrulefill\\ (g\circ f)(5)=g(~~f(5)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(5)=3(5)+2\implies f(5)=17 \\\\[-0.35em] ~\dotfill\\\\ g(~~f(5)~~)\implies g(~~17~~)=(17)^2-3(17)-4\implies g(17)=289-58-4 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \stackrel{(g\circ f)(5)}{g(17)=227}~\hfill

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Please help me with the whole page. I need the answers and calculations please!
Harman [31]
4: (3/4 - 1/2) X 3/5. 

You need them all to have the same denominator (bottom number) 
The lowest common denominator (LCM) of 2,4 and 5 is 20
4 X 5 = 20
2 X 10 = 20
5 X 4 = 20 

Then multiply the top number by the amount you need to multiply the bottom number by to get 20

3 X 5 = 15
1 X 10 = 10
3 X 4 = 12

(3/4 - 1/2) X 3/5. Turns to (15/20 - 10/20) X 12/20.

15 - 10  = 5
5 X 12 = 60

Answer: 60/20
Simplified: Either 3 or 3/1.



If you use the steps above then you should be able to do the rest :D
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