Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form
is equal to

where
The <u>discriminant</u> of the <u>quadratic equation</u> is equal to

if
----> the <u>quadratic equation</u> has two <u>real roots</u>
if
----> the <u>quadratic equation</u> has one <u>real root</u>
if
----> the <u>quadratic equation</u> has two <u>complex roots</u>
in this problem we have that
the <u>discriminant</u> is equal to 
so
the <u>quadratic equation</u> has two <u>complex roots</u>
therefore
the answer is the option A
There are two complex roots
50+ 7.99 x =y
50+ 7.99 (40)= y
50+319.60= y
369.60=y
50+ 7.99 x =y
50 + 7.99 (50)
50+ 399.50=449.50
6.99(30)=209.70
449.50 + 209.70 =659.2
Answer:
12
Step-by-step explanation:
Given: Diagonal of square= 
To find the perimeter of square, we need to find the length of sides of square.
∴ Using the formula of diagonal to find side of square.
Formula; 
Where, s is side of square.
⇒ 
Dividing both side by √2
⇒
∴
Hence, Length of side of square is 3.
Now, finding the perimeter of square.
Formula; 
⇒
∴ 
Hence, Perimeter of square is 12.
the answer for this would be the last one. two rays that meet at a end point.
hope this helps!