∠AED is formed inside a circle by two intersecting chords. If minor arc BD = 70 and minor arc CA = 180, what is the measure of ∠

Question

3 years ago

6

AED?

2 answers:

Usimov [2.4K] · Answer 1 · 2022-05-18T06:25:41+03:00

4 0

I was think vertical angle.

Anvisha [2.4K] · Answer 2 · 2022-05-18T07:40:52+03:00

Answer:

∠AED = 55°

Step-by-step explanation:

Two chords AB and CD are intersecting each other at E. Minor arc BD is = 70 and minor arc CA is = 180.

We have to find the measurement of ∠AED.

Now we know that ∠CEA = $\frac{1}{2}(arcBD+arcCA)=\frac{1}{2}(70+180)=\frac{1}{2}(250)=125$

Since ∠CEA + ∠AED = 180° [ Supplementary angles ]

125° + ∠AED = 180

∠AED = 180 - 125 = 55°

Therefore measure of the angle AED = 55° is the answer.