Question

PLEASE HELP ASAP: Sals sandwich shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit on every wrap is $3. Sal made a profit of 1470 from lunch special last month, where x is the number of sandwich lunch specials sold y is the number of wrap lunch specials sold. 4. Graph the function using one of the following two options below. On the graph, make sure to label the intercepts.

Answer 1

Answer:

y intercept (0,490)

I would use (Graphing equation standard form) to identify x and y intercepts. I will Plot the y intercept (0,490) and the x intercept (735,0)

,It will Connect the two intercepts with a straight line

2x + 3y = 1,470

3y = -2x + 1470

y = (-2x + 1470 ) / 3

y = -2/3 * x + 1470/3

y = -2/3 * x + 490

slope is -2/3

y intercept is 490

x intercept (735,0)

Step-by-step explanation:

Answer 2

Answer:

$2x+3y=1470$

Step-by-step explanation:

Givens

• The profit on every sandwich is $2.
• The profit on every wrap is $3.
• Sal made $1470 in profits.

So, $x$ represents the number of sandwiches and $y$ represents the number of wraps, so the profit on each food is

$2x$ and $3y$, so the sum of them must be equal to $1470, as follows

$2x+3y=1470$

Which is a linear equation, that means if we graph, it would be a line.

To graph this, we just need to find two points.

For $x=0$, let's find $y$

$2x+3y=1470\\2(0)+3y=1470\\y=\frac{1470}{3}=490$

For $y=0$. let's find $x$

$2x+3y=1470\\2x+3(0)=1470\\x=\frac{1470}{2}=735$

Therefore, the two points to graph the line are $(0,490)$ and $(735, 0)$. Now, we graph these coordinates and draw a line that must cross them

The resulting graph should be like the image attached.