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lisov135 [29]
3 years ago
15

There are 12,boys and 10 girls in your gym class. If 6 boys joined the class, how many girls would need to join for the ratio to

remain the same?
Mathematics
2 answers:
nordsb [41]3 years ago
6 0
The number of girls that need to join the gym class to keep the ratio same is 5.

Savatey [412]3 years ago
5 0
6 girls would need to join for the ratio to be the same
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Three vertices of square WXYZ are W(1, 4), X(4, 0), and Y(0, –3). What are the coordinates of the fourth vertex?
BARSIC [14]
Hello,

Z=(-3,1)
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8 0
3 years ago
Quadrilateral ABCD ​ is inscribed in this circle.
Lelechka [254]

Answer:

m∠C = 122°

Step-by-step explanation:

Opposite angles of a quadrilateral inscribed in a circle are supplementary. This means

m∠A + m∠C = 180°

m∠B + m∠D = 180°

To find angle C we need to find x, then subtract m∠A from 180°

x+20=3x

20=2x

x=10

Now we substitute 10 in for x

m∠A=2(10)+38

m∠A=20+38

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m∠C=180-58

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4 0
3 years ago
What is 3+100
dedylja [7]
3+100 is 69 plus 34 :)
5 0
3 years ago
Read 2 more answers
Why is this false:
Luba_88 [7]

Answer:

It is false that, if the national economy shrank at an annual rate of 9% per year for three consecutive years then the economy shrank by 27% over the 3-year period, because this percentage does not follow a linear path, but on the contrary, it is calculated exponentially: 9% of each year is calculated on the rest that remained after discounting 9% the previous year.

Thus, if the national economy has a value of 100, after three years it will not have a value of 79, but a value of 75.35, as it arises from the following calculation:

100 x 0.91 ^ 3 = X

100 x 0.753571 = X

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5 0
3 years ago
A fair die is rolled 5 times. What is the probability that a 3 is obtained on at least one of the rolls? Round your answer to th
Lerok [7]

Answer:

0.200

Step-by-step explanation:

The probability of obtaining a 3, in one roll of a fair die is 1/6.

Now, we have 5 rolls.

We now want to know the probability of a 3 showing up in at least one of the rolls.

This simply mean, we add the probabilities of three showing one time plus probability of three showing in 2 of the rolls e.t.c

This means we can have 3 showing up to 5 times.

We add the probabilities as follows:

(1/6) + (1/6)^2 + (1/6)^3 + (1/6)^4 + (1/6)^5 = 0.199974 = 0.200

3 0
3 years ago
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