Answer:
No he is not lol 16÷4=4, To buy 10, 10×4=40. 40-35=5 he needs 5 dollars more
Whats the normal arm span for these heights? : 4'10,4'11,5'0,5'4,5'5,5,'7,5'8,5'9,5'10,5'11,6'0
Svetllana [295]
In adults, the arm span is approximately 5 cm greater than the height in adult males and 1.2 cm in
adult females. To calculate the arm span for the heights given, we add
5cm to their height. The following are the results:
Height Arm Span Length (in cm)
4’10 152.32
4’11 154.86
5’0 157.4
5’4 167.56
5’5 170.10
5’7 175.18
5’8 177.72
5’9 180.26
5’10 182.80
5’11 185.34
6’0 187.88
To add, the total measurement of the length from the furthermost
part of an individual's arms to the other end
when raised equidistant to the ground at shoulder height at a 90º angle
is called the arm span or wingspan.
the square root of 5000 is 71 (rounded to the nearest)
K-7.2>2.1.
+7.2 +7.2
------------------
k> 9.3
are you suppose to solve for k?
Answer
so there are 7 singing acts and 5 comedy acts.
Step-by-step explanation:
Let x= number of singing acts.
Let y= number of comedy acts.
We will take x+y=12 as our first equation, as there are 12 shows in total. We will take 5x+3y=50 as our second equation as there are 50 total minutes, and singing acts are 5 mins and comedy acts are 3 mins.
We solve x+y=12
Y=-x+12
We know y=-x+12, so we will substitute that for the y in the second equation.
1. Substitute 5x+3(-x+12)=50
2. Distribute 5x-3x+36=50
3. Solve 2x+36=50
2x=14
X=7
Now that we have found x, we will find y by substitute the x in 5x+3y=50 with the value, 7, that we found for x.
5(7)+3y=50
35+3y=50
3y=15
Y=5
