The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
<h3>What is the radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.?</h3>
Generally, the equation for side lengths AB is mathematically given as
Triangle ABC has side lengths
Where
- AB = 65,
- BC = 33,
- AC = 56.
Hence
r √ 2 · (89 √ 2/2 − r √ 2) = r(89 − 2r),
r = 89 − 65
r= 24.
In conclusion, The radius of the circle tangent to sides AC and BC and to the circumcircle of triangle ABC.
r= 24.
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Answer:
y=-x-5
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-8-(-1))/(3-(-4))
m=(-8+1)/(3+4)
m=-7/7
m=-1
y-y1=m(x-x1)
y-(-1)=-1(x-(-4))
y+1=-1(x+4)
y+1=-x-4
y=-x-4-1
y=-x-5
Please mark me as Brainliest if you're satisfied with the answer.
Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic
10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)
Final Answer: 10
Answer:
Yes I think it is a Linear function
Answer:
25%
Step-by-step explanation:
Percentage increase is calculated as
% increase = 
× 100%
Increase = 30 - 24 = 6, thus
% increase = 
× 100% = 0.25 × 100% = 25%
