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3 years ago

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What would 1/27 -1 be?

1 answer:

ahrayia [7]3 years ago

6 0

Make denominator common,

1/27 - 27/27 = (1-27)/27 = -26/27

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Charles is making pumpkin lattes. His recipe calls for 2/3 cup of milk for every eighth cup of pumpkin purée. If Charles is maki

Molodets [167]

Are we assuming that we are using an eight of a cup of pumpkin puree per latte?
If we are then the answer would be 1.042 cups of milk more than puree.

First we have to find out how much puree we are using.
That would be ( 1/8 ) × 5 = 0.125 × 5 = 0.625 cups of puree.
Then we would find how much milk we are using.
That would be ( 2/3 ) × 5 = 0.666666 ( a lot of sixes ) × 5 = 1.666666 ( a lot of sixes ).
To find the difference, you would then have to subtract the amount of puree from the amount of milk.
You would get 1.666666 − 0.625 = 1.0416666 ( also a lot of sixes ). If you are doing this with your own calculator you should get approximately the same number.
Since the number isn't exact you can round up all the sixes to the nearest thousandth. You should get approximately 1.042 cups.
I hope this helped.

7 0

3 years ago

Simplify 4x +3+x² – x

jeka57 [31]

Answer:

x^2+3x+3

Step-by-step explanation:

6 0

3 years ago

X + 6<br> 2<br> − <br> x − 8<br> 7<br> = 2

mina [271]

first take 62 -8 = 54 x 87=4698 then take 4698-2 and get 4696

3 0

4 years ago

<img src="https://tex.z-dn.net/?f=%24a%2Ba%20r%2Ba%20r%5E%7B2%7D%2B%5Cldots%20%5Cinfty%3D15%24%24a%5E%7B2%7D%2B%28a%20r%29%5E%7B

riadik2000 [5.3K]

Let

$S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n$

where we assume |r| < 1. Multiplying on both sides by r gives

$r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}$

and subtracting this from $S_n$ gives

$(1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}$

As n → ∞, the exponential term will converge to 0, and the partial sums $S_n$ will converge to

$\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}$

Now, we're given

$a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a$

$a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}$

We must have |r| < 1 since both sums converge, so

$\dfrac{15}a = \dfrac1{1-r}$

$\dfrac{150}{a^2} = \dfrac1{1-r^2}$

Solving for r by substitution, we have

$\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)$

$\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}$

Recalling the difference of squares identity, we have

$\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}$

We've already confirmed r ≠ 1, so we can simplify this to

$\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15$

It follows that

$\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12$

and so the sum we want is

$ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}$

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

7 0

3 years ago

How do I find x in this triangle?

timama [110]

Answer:

B=5

Step-by-step explanation:

a2+b2=c2

12squared+b2=13squared

144+b2=169 Subtract by 144 on both sides

b2=25 Find square root of 25

b=5

5 0

3 years ago