The unit rate is basically her progress every hour so...
1.5 hours = 2/7
1 hour = 2/7 x 2/3 = 4/21
answer: 4/21 per hour
Answer:
the answer is -1.8
Step-by-step explanation:
Answer:
0.72secs
Step-by-step explanation:
Given the height of the ball in air modeled by the equation:
h=−16t²+23t+4
Required
Total time it spent in the air
To get this we need to calculate its time at the maximum height
At the maximum height,
v = dh/dt = 0
-32t + 23 = 0
-32t = -23
t = 23/32
t = 0.72secs
<em>Hence the total time it spend in the air will be 0.72secs</em>
9514 1404 393
Answer:
- cable length: 300.2 ft
- anchor distance: 193.0 ft
Step-by-step explanation:
The side given is opposite the given angle. We want to find both the hypotenuse and the adjacent side in the right triangle that models the geometry.
Sin = Opposite/Hypotenuse
sin(50°) = (230 ft)/h
h = (230 ft)/sin(50°) ≈ 300.24 ft
The length of the cable must be about 300.2 feet.
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Tan = Opposite/Adjacent
tan(50°) = (230 ft)/d
d = (230 ft)/tan(50°) ≈ 192.99 ft
The cable must be anchored about 193.0 ft from the tower.
Answer:p=qbecause they are the same
Step-by-step explanation: