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stepladder [879]
3 years ago
7

What is the cube root of 27a^12

Mathematics
2 answers:
harkovskaia [24]3 years ago
7 0
Cube root (27a^12)
Cube root 27 = 3 because
3 * 3 * 3 = 27
Cube root a^12 = a^4 because
a^4 * a^4 * a^4 = a^12
ANSWER
3a^4
Alika [10]3 years ago
6 0

Answer:

3 \times a^{4}

Step-by-step explanation:

We have to find the cube root of the given expression 27a^{12}

\sqrt[3]{27a^{12}} = \sqrt[3]{27} \times\sqrt[3]{a^{12}}

= \sqrt[3]{3\times3\times3} \times\sqrt[3]{a^{4} \times a^{4} \times a^{4}}

= 3 \times a^{4}

Therefore, 3 \times a^{4} is the answer.

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Evaluate the expression for x = 2 and y = 4. Enter your answer in the box.<br><br> 16x0 + 2x2 • y –1
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Given that,

The given expression is : 16x^0+2x^2{\cdot}y^{-1}

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