Answer:
1) M(x) = 5 + 3x
2) Dependent variable; 3 dollar bills
Independent variable: chores
3) Range is continuous
Domain is discrete
4) Range: 0 ≤ x ≤ 10
Domain: 5 ≤ M ≤ 35
Step-by-step explanation:
We are told he started with 5 number of $1 dollar bills and that every Saturday, he earns 3 more $1 dollar bill.
Thus, total number of $1 bills earned after x number of Saturdays(weekly) is;
M(x) = 5 + 3x
After 10 weeks, total number is;
M(10) = 5 + 3(10)
M(10) = 35
The dependent variable is the 3 more dollar bills earned each Saturday because it depends on chores he completed. While the independent variable is the chores because it doesn't depend on anything.
After 10 weeks, the range and domain will be;
Range: 0 ≤ x ≤ 10
For the; Domain:
For x = 1, M(0) = 5 + 3(0) = 5
M(10) = 35
Thus;
Domain: 5 ≤ M ≤ 35
The range could be all numbers in the interval from 0 to 10. Thus, it is continuous.
Whereas, the domain doesn't contain all the numbers in the interval from 5 to 35. Thus it is Discrete.
<h3>
Answer: 5</h3>
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Explanation:
Let's consider the expression (x-y)^2. It expands out to x^2-2xy+y^2. The terms are:
Each of those terms either has a single variable with an exponent of 2, or has the exponents add to 2. Think of 2xy as 2x^1y^1.
In short, this means that the degree of each monomial term is 2.
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Now consider (x-y)^3. It expands out into x^3-3x^2y+3xy^2+y^3.
We have terms that either have a single variable and the exponent is 3, or the exponents add to 3. The degree of each term is 3.
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This pattern continues.
In general, for (x-y)^n, where n is any positive whole number, the degree of each term in the expansion is n. If you picked any term, added the exponents, then the exponents will add to n.
Answer:
step 2
Step-by-step explanation:
Given step 1
324π = π × 12² h
Then second step should read
324π = π × 144h ← 144 not 24 is the error
Answer:
A is the midpoint
Step-by-step explanation:
Given
A(5.2) B(6,-3) and C(4.7)
Required
Which is the midpoint
Midpoint is calculated using:
Testing A as the midpoint, we have:
<em>The above equation is true. Hence, A is the midpoint of B and C</em>
