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vesna_86 [32]
3 years ago
13

Which postulate can be used to prove that the triangles are congruent?

Mathematics
1 answer:
marin [14]3 years ago
6 0

<u>Answer:</u>

The correct answer option is 'not congruent'.

<u>Step-by-step explanation:</u>

We are given two right angled triangles and we to to determine if their congruence can be proved by any postulate.

Two right angled triangles are said to be congruent if the hypotenuse and one leg of a right-angled triangle are equal to the corresponding hypotenuse and leg of another right-angled triangle.

While here, the hypotenuse of each of the triangles are not equal and neither their corresponding legs.

Therefore, these triangles are not congruent.

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Help me with this geometry question please
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3 years ago
Determine the equations of the vertical and horizontal asymptotes, if any, for f(x)=2x/x+4
slamgirl [31]

Answer:

Vertical asymptote:x=-4

Horizontal asymptote: y=2

Step-by-step explanation:

The given rational function is

f(x)=\frac{2x}{x+4}

To find the vertical asymptote we equate the denominator to zero and solve for x.

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The equation of the vertical asymptote is

x=-4

To find the horizontal asymptote we take limit to infinity. Or simply express the coefficient of x in the numerator over the coefficient of x in the denominator since this is a proper rational function.

The horizontal asymptote has equation

y=\frac{2}{1} =2

7 0
4 years ago
What type of transformation moved the pre-image to this image?
sergij07 [2.7K]

Answer:

Dilation

Hope that helps!

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
1a. what is the slope. 1b. what is the y- intercept 1c. write the equation. PLEASE HELP IM DOING HOMEWORK AND ITS 1:00am
Sedaia [141]

the slope is 1 cos its goin ovr one, up one

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iiiif you write it using y=mx+b,, m is the slope n b is the y int so itd jus be: y=x+3

6 0
3 years ago
a chef uses 4 3/4 cups of broth for 10 servings of soup.how much broth is is one serving . let x represent amount. 4 3/4/10 =x/1
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Let's firstly convert the mixed fraction to "improper" and then proceed,

\bf \begin{array}{ccll}&#10;\stackrel{broth}{cups}&servings\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;4\frac{3}{4}&10\\\\&#10;x&1&#10;\end{array}\implies \cfrac{\quad \stackrel{mixed}{4\frac{3}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{4\cdot 4+3}{4}\quad }{x}=\cfrac{10}{1}

\bf \cfrac{\quad \stackrel{improper}{\frac{19}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{19}{4}\quad }{\frac{x}{1}}=\cfrac{10}{1}\implies \cfrac{19}{4}\cdot \cfrac{1}{x}=\cfrac{10}{1}\implies \cfrac{19}{4x}=\cfrac{10}{1}&#10;\\\\\\&#10;19=40x\implies \cfrac{19}{40}=x
6 0
4 years ago
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