Which expressions are equivalent to 2(2x + 4y + x − 2y)?

We need to know what the best buy is for purchasing t-shirts at three different stores.

expeople1 [14]

Answer:
A- 25.48 divided by 6 = 4.246666666666667 (just round it up or down)

B- 17.99 divided by 4= 4.4975

C- 21.09 divided by 5= 4.218

D- Amazon

5 0

3 years ago

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Alvin is 15 younger than elga the sum of their age is 27 what is elga age

zloy xaker [14]

Answer:

27 years old

Step-by-step explanation:

Let Alvin's age be x and Elga's age is y:

y - x = 15

x + y = 27

2y = 42 (use elimination method)

y = 21

x = 6 (plug it back into either equation)

Therefore Alvin is 6 and Elga is 27

7 0

3 years ago

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Arduino language is based on__ programming language.

asambeis [7]

Answer: Normally C/C++

Step-by-step explanation:

5 0

3 years ago

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A circle has a radius of 6 feet. Calculate the area of the<br> sector formed by a central 30° angle

Tems11 [23]

Answer:

The area of the sector is 9.43 ft^2

Step-by-step explanation:

Here, we want to find the area of the sector with a central angle of 30 degrees

To do this, we use the formula below;

Area of sector = theta/360 * pi * r^2

theta = central angle = 30 degrees

r = radius = 6 ft

Thus, we have it that;

Area of sector = 30/360 * pi * 6^2

= 30/10 * pi = 3 * 3.142 = 9.43 ft^2

6 0

3 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$