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cestrela7 [59]
3 years ago
8

ABC Tax Planning Service started business in January 2018. The company rented an office for $5,400 per month starting from Janua

ry 1, 2018. On that day, ABC prepaid the rent through June 30. The company makes adjusting entries at the end of each month. What is the balance in the Prepaid Rent account as of April 30, 2018?
Business
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

balance in the Prepaid Rent account as of April 30 is $10800

Explanation:

given data

rent office =  $5,400 per month

rent paid = 6 month i.e January 1 to June 30

to find out

balance in the Prepaid Rent account as of April 30

solution

we know here that Period Expired till April 30 = 4 months ( January 1 to April 30)

and

so Period Balance = 2 Months  ( May 1 to June 30 )

so Prepaid Rent is = Balance Period × Rent per month

Prepaid Rent = 2  × 5,400

Prepaid Rent = $10800

so balance in the Prepaid Rent account as of April 30 is $10800

You might be interested in
You are a network engineer for a midsized government contractor working on a project for a national government lab. Your network
vaieri [72.5K]

Answer:

In creating a Bill of Material for the infrastructure and tools for the lab, we need to create certain test plans, by having to test applications anf devices that will work in a new environment

Infrastructures devices in the IPv6 lab is needed such as switches, routers, firewalls.

End systems are important with various operating systems and application that is hosted in a fictional network.

At the end of the day, it might be costly, but durability is rest assured on the long period of time.

Explanation:

Solution

By setting up a IPv6 and converting labs from IPv4 to IPv6 is not only tasking, but we need to create or design certain test plans.

We  test how applications and devices will work in a new environment and this set up will be like a real world environment  (scenario)

This IPv6 lab will need infrastructure devices like routers, firewalls, routers, switches.

With the addition of infrastructure devices it also needs end systems with various operating systems. and  applications that are hosted in the operational network

All these things will cost but  the durability is assured on the long period.

Setting up a full lab set up may costly but it provides an environment where we can test application and infrastructure safely.  this type of system testing will give insights to how the system will function when we allocated operationally . this will helps to reduce cost  and if we want test these for multiple labs we can develop a tunnel.

Tunnel Is nothing but a native common thing that connects all the labs that want to initiate an IPv4.

Because of time and cost both will decrease and infrastructure durability increases and performance .

6 0
3 years ago
To automate one of its production​ processes, the Milwaukee Corporation bought three flexible manufacturing cells at a price of
liq [111]

Answer:

$1,521,800

Explanation:

The computation of cost basis is shown below:-

Three cells cost price = 3 × $470,000

= $1,410,000

Combination of rate charges = $30,000 + $16,000 + $39,000 + $3,600

= $88,600

Wages of one foreman = wage per hour × weeks worked × hours per week

= $29 × 5 × 40

= $5,800

Wages of 4 foremen = 4 × $5,800

= $23,200

Three cells cost basis = Three cells cost price + Combination of rate charges + Wages of one foreman

= $1,410,000 + $88,600 + $23,200

= $1,521,800

4 0
3 years ago
Which of the following is not true in regard to selling fixed assets?
hichkok12 [17]
Your answer is C. Accumulated Depreciation will be credited. :D
5 0
3 years ago
He allowance method of estimating uncollectible accounts receivable based on an analysis of receivables shows that $640 of accou
dsp73

Answer: <u><em>The adjusting entry at the end of the year will include a credit to Allowance for Doubtful Accounts in the amount of:  $750</em></u>

Given:

Accounts receivable = $640

Allowance for Doubtful Accounts = $110

<em><u></u></em>

<em><u>Therefore, the correct option is (c).</u></em>

4 0
4 years ago
A manufacturer estimates that its product can be produced at a total cost of C(x) = 50,000 + 100x + x3 dollars. If the manufactu
timofeeve [1]

Answer:

The level of production x that will maximize the profit is: 22,966

Explanation:

C(x) = 50,000 + 100x + x³

R(x) = 3400x

P(x) = R(x) - C(x)

      = 3400x - [50,000 + 100x + x³]

      = 3400x - 50,000 - 100x - x³

      = 3300x - 50,000 - x³   .................... (A)

P'(x) = 3300(1) - 0 - 3x²

       = 3300 - 3x²

At a critical point, P'(x) = 0

∴   0 = 3300 - 3x²

  3x² = 3300

    x² = 1100

     x = ± \sqrt{1100}

P"(x) = -6x

P(\sqrt{1100}) = -6 (\sqrt{1100})   < 0

by second derivative, 'P' max at    x = \sqrt{1100} = 33.17 (rounds)

since x =  \sqrt{1100} ,

recall that P(x) = 3300x - 50,000 - x³ from equation (A)

Therefore, Maximum Profit

P(\sqrt{1100}) = 3300\sqrt{1100} - 50000 - \sqrt{1100} ^{3}

              = 3300(33.17) - 50,000 - 33.17³

              = 109461 -50,000 - 36495.26

              = 22,965.74

Maximum profit is 22,966 to the nearest whole number

5 0
3 years ago
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