Answer:
its the biceps
hopw it helpsand plz mark me the brainliest
Answer No 2:
c c
C Cc Cc
c cc cc
The genotype of the offsprings would be Cc, Cc, cc, cc i.e heterozygous cleft chin and no cleft chin. The phenotype of the offsprings could be 50% cleft chin and 50% without cleft chin.
there will be 50% chance of the child to have cleft chin.
Answer No 3:
A a
A Aa Aa
a Aa aa
There will be 25% chance for the offspring to have arched feet. As arched feet is a recessive trait, so for this trait to occur both the alleles of the gene should be recessive i.e aa.
Answer No 4:
B b
b Bb bb
b Bb bb
As blonde is a recessive trait, so both the alleles for this gene should be recessive for this trait to occur. Hence, according to the punnet square, there will be 50% chance for the offspring to be blonde.
Answer No 5:
F f
F FF Ff
f Ff ff
As normal vision is a resessive trait, hence both the alleles of the gene should be recessive for the trait to occur. According to the punnet square, there is 25% chance that the child will have normal vision.
Answer:
pfu/ml
Explanation:
Given -
Bacteriophage dilution 
ml
Volume of bacteria and plate with top agar 
ml
Number of plaques 
pfu
Dilution (d) 
Final concentration of phage stock is equal to
Where pfu is the count of plaques
d is the dilution and v is the volume
Substituting the given values, we get -
pfu/ml
