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lidiya [134]
2 years ago
5

Determine the factors of the expression x^2 - 9

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
5 0

Answer:

Step-by-step explanation:


The answer is B.


Use the sum-product pattern


2+3−3−9



Common factor from the two pairs


2+3−3−9x2+3x−3x−9


(+3)−3(+3)

Rewrite in factored form


(+3)−3(+3)


Solution:

(−3)(+3)

‘Hope it Helps!

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What is the answer to 3/7w-11=4/7w
stellarik [79]
\frac{3}{7}w-11=\frac{4}{7}w\ \ \ \ \ \ \ |\cdot7\\\\3w-77=4w\\\\-77=4w-3w\\\\w=-77\\\\Answer\ is\ -77.
7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!
Alexxx [7]

(x - 5i√2)(x +5i√2)

given the roots of a polynomial p(x), say x = a and x = b

then the factors are (x - a)(x - b)

and p(x) is the product of the factors ⇒ p(x) = (x - a)(x - b)

here x² + 50 = 0 ⇒ x² = - 50 → ( set = 0 for roots)

take the square root of both sides

x = ± √-50 = ±  √(25 × 2 × -1) = √25 × √2 × √-1 = ± 5i√2

The roots are x = ± 5i√2

thus the factors are ( x - ( - 5i√2)) and (x - (+5i√2))

x² + 50 = (x + 5i√2)(x - 5i√2)


8 0
3 years ago
Orange M&M’s: The M&M’s web site says that 20% of milk chocolate M&M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
Solve for x. <br> x/9 = -5
arlik [135]
X=-45 hope that helps!
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3 years ago
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Given an expression can you write an equivalent form of the expression and explain the properties you used?
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What is the expression? Tell me and I will help you.
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