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madreJ [45]
3 years ago
9

Solve for x someone help please. If possible please include steps

Mathematics
2 answers:
meriva3 years ago
7 0

Answer:x = 10

Step-by-step explanation:

olga55 [171]3 years ago
4 0

Answer:

10

Step-by-step explanation:

(x + 2) + (-2 + x) = 20

2x + 0 = 20

2x = 20

x = 20/2

x = 10

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Scale Factor (Dilation) The scale factor in the dilation of a mathematical object determines how much larger or smaller the image will be (compared to the original object). When the absolute value of the scale factor is greater than one, an expansion occurs.

8 0
3 years ago
Determine the solution to the equation.
postnew [5]
Answer : x = 25

5 x=32−7
5 x = 25
25x = 625
x=625/25
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8 0
3 years ago
At a new exhibit in the museum of science, people are asked to choose between 90 or 120 random draws from a machine. The machine
Serga [27]

Answer:

There is a probability of P₉₀=0.09853 of winning the prize with a 90-balls sample.

There is a probability of P₁₂₀=0.0853 of winning the prize with a 120-balls sample.

Step-by-step explanation:

In this problem, the balls that are removed are then replaced in the total, so the probability of obtaining a green ball is constant and is equal to:

P_g=\frac{93}{93+65}= 0.5886

This type of sampling should be analyzed with the binomial distribution, but given the sample size, it is convenient to use the approximation to a normal distribution.

The parameters of the normal distribution are:

\mu=P_g*n=0.5886*90=52.9746\\\\\sigma=\sqrt{np(1-p)}=\sqrt{90*0.5886*(1-0.5886)} =4.6684

To win the prize it is needed at least 65% of green balls in the sample, which means there have to be at least 59 green balls in the sample:

0.65*90=58.5

To calculate the probability of getting 59 or more green balls, we have to calculate the z-value

z=\frac{x-\mu}{\sigma}=\frac{59-52.9746}{4.6684}= 1.29

Then, the probability can be look up with the z-value in a normal distribution table:

P(X \geq  59)=P(z\geq 1.29)=0.09853

There is a probability of P=0.09853 of winning the prize with a 90-balls sample.

When the sample is of 120 balls, we have to recalculate the parameters.

Normal distribution

\mu=P_g*n=0.5886*120=70.6320\\\\\sigma=\sqrt{np(1-p)}=\sqrt{120*0.5886*(1-0.5886)} =5.3905

To win the prize it is needed at least 65% of green balls in the sample, which means there have to be at least 78 green balls in the sample:

0.65*120=78

To calculate the probability of getting 78 or more green balls, we have to calculate the z-value

z=\frac{x-\mu}{\sigma}=\frac{78-70.6320}{5.3905}=1.37

Then, the probability can be look up with the z-value in a normal distribution table:

P(X \geq 78 )=P(z\geq 1.37)=0.0853

There is a probability of P=0.0853 of winning the prize with a 120-balls sample.

8 0
3 years ago
Marty has 2 4/5 quarts of juice. he pours the same amount of juice into 2 bottles. how much does he pour into each bottle?
Ad libitum [116K]
2.8!!!!!! ;pppppppp-
8 0
3 years ago
The radii of two cylinders are in the ratio 1 : 4 and their heights are in the ratio 3 : 1. The ratio of their lateral surface a
Montano1993 [528]

Answer:

a

Step-by-step explanation:

Cylinders:

Ratio of radii = 1 : 4

Radius of two cylinders are: r , 4r

Ratio of height = 3 :1

Height of two cylinders are: 3h , h

Lateral surface area of cylinder =  2πrh

Ratio of lateral surface area= 2π* r * 3h   : 2π* 4r * h

                                             = 3 : 4

8 0
3 years ago
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