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andrey2020 [161]
3 years ago
7

A jar contains 16 beads. 4 beads are red, 5are yellow, and 3 are blue. What is the probability of picking a blue bead ?

Mathematics
2 answers:
mamaluj [8]3 years ago
6 0

Answer:

4/16

Step-by-step explanation:

erma4kov [3.2K]3 years ago
5 0

Answer:

Unlikely because there are less blue than any other color.

Step-by-step explanation:

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Answer:

\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2=4(3+3\sqrt{2})

Step-by-step explanation:

Considering the radical expression

\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2

​\mathrm{Apply\:exponent\:rule}:\quad \left(a\cdot \:b\right)^n=a^nb^n

=2^2\left(\sqrt{3+3\sqrt{2}}\right)^2.....[A]

Simplifying

\left(\sqrt{3+3\sqrt{2}}\right)^2

\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}=a^{\frac{1}{2}}

=\left(\left(3+3\sqrt{2}\right)^{\frac{1}{2}}\right)^2

\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc}

=\left(3+3\sqrt{2}\right)^{\frac{1}{2}\cdot \:2}

=3+3\sqrt{2}          As \frac{1}{2}\cdot \:2=1

So, putting 3+3\sqrt{2} into Equation [A]

=2^2\left(\sqrt{3+3\sqrt{2}}\right)^2.....[A]

As

\left(\sqrt{3+3\sqrt{2}}\right)^2=3+3\sqrt{2}

So, Equation [A] becomes

=2^{2}(3+3\sqrt{2})

=4(3+3\sqrt{2})

Therefore,

\left(2\:\sqrt{3\:+\:3\:\sqrt{2}\:\:}\:\right)\:^2=4(3+3\sqrt{2})

Keywords: radical expression

Learn more radical expression from brainly.com/question/11624221

#learnwithBrainly

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