Let's assume we were given 2 numbers: 15 and 30. Their sum is:
We want to express it as the product of GCF and another sum.
15 is divisible by: 1, 3, 5, 15
30 is divisible by: 1, 2, 3, 5, 6, 10, 15, 30
The greatest number that appears in 2 series is 15.
In this case sum of two numbers can always be written as:
7=3(5+x). 7 represents the pay altogether. 3 represents the total number of people. 5 represents the price of a ticket +x which represents the coupon
The value of can never be 0
y = 0
A
<h2>Hello There today we will solve your problem</h2>
<em>Response-</em>
<em>ABC is absolutely a right triangle</em>
<em>we can use the pythagorean theorem to solve this</em>
<h3><em>Definitions</em></h3>
Right Triangle - <em>A right triangle or right-angled triangle, or more formally an orthogonal triangle, is a triangle in which one angle is a right angle. The relation between the sides and other angles of the right triangle is the basis for trigonometry. The side opposite to the right angle is called the hypotenuse.</em>
Pythagorean Theorem - <em>In mathematics, the Pythagorean theorem, or Pythagoras' theorem, is a fundamental relation in Euclidean geometry among the three sides of a right triangle. It states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides.</em>
<em>_________________</em>
<em>To use to the Pythagorean Theorem it is</em>
For our equation 
would be 
would be 
<em>_________________</em>
<h2><em>Solve</em></h2>
Since we got 
this is a right triangle since it's what we had before.
Step-by-step explanation:
This is a probability related question, let the event be E
We know that the likelihood of an event happening is given as
Pr(E)=1
if an event will not occur the probability is
Pr(E)=0
a. This event is impossible: Pr(E)=0
b.This event will occur more often than not, but is not extremely likely:
Pr(E)=0<E>0.5
c.This event is extremely unlikely, but it will occur once in a while in a long sequence of trials:
Pr(E)=0<E<0.5
d.This event will occur for sure: Pr(E)=0
