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SCORPION-xisa [38]
4 years ago
5

............................

Mathematics
2 answers:
storchak [24]4 years ago
7 0

The answer is 39 hope this helps

aksik [14]4 years ago
3 0
858 divided by 22 is 39....hope this helps
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What is the answer to 6(-3-4y) simplifying algebriac expressions
Mekhanik [1.2K]

Answer:

-18 - 24y.

Step-by-step explanation:

6(-3-4y)

We use the distributive law to give:

6 * -3 + 6* -4y

= -18 - 24y.

6 0
3 years ago
Let vector F = (6 x^2 y + 2 y^3 + 4 e^x) i + (7 e^{y^2} + 54 x) j . Consider the line integral of vector F around the circle of
balu736 [363]

Denote the circle of radius a by C. C is simple and closed, so by Green's theorem the line integral reduces to a double integral over the interior of C (call it D):

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_C(6x^2y+2y^3+4e^x)\,\mathrm dx+(7e^{y^2}+54x)\,\mathrm dy

=\displaystyle\iint_D\left(\frac{\partial(7e^{y^2}+54x)}{\partial x}-\frac{\partial(6x^2y+2y^3+4e^x)}{\partial y}\right)\,\mathrm dx\,\mathrm dy

=\displaystyle\iint_D(54-6x^2-6y^2)\,\mathrm dx\,\mathrm dy

D is a circle of radius a, so we can write the double integral in polar coordinates as

\displaystyle\iint_D(54-6x^2-6y^2)\,\mathrm dx\,\mathrm dy=\int_0^{2\pi}\int_0^a(54-6r^2)r\,\mathrm dr\,\mathrm d\theta

a. For a=1, we have

\displaystyle\int_0^{2\pi}\int_0^1(54-6r^2)r\,\mathrm dr\,\mathrm d\theta=2\pi\int_0^1(54r-6r^3)\,\mathrm dr=\boxed{51\pi}

b. Let I(a) denote the integral with unknown parameter a,

I(a)=12\pi\int_0^a(9r-r^3)\,\mathrm dr\,\mathrm d\theta

By the fundamental theorem of calculus,

I'(a)=12\pi(9a-a^3)

I(a) has critical points when

12\pi(9a-a^3)=12\pi a(9-a^2)=0\implies a=0,a=\pm3

If a=0, then line integral is 0, so we ignore that critical point. For the other two, we would find I(\pm3)=243\pi.

8 0
3 years ago
Add 3 feet 6 inches +8 feet 2 inches +4 inches +2feet 5 inches
enyata [817]
You will just get 18 feet 3inches or 18.3 feet
8 0
3 years ago
Read 2 more answers
The difference of a number divided by 3 and 9 is equal to 8<br> .
padilas [110]
<span>two divided by the difference of a number and 3 minus 4 divided by a number plus 3, equals 8 times the reciprocal of the difference of the number squared and 9.

let x=number
2/(x-3)-4/(x+3)=8/(x^2-9)=8/(x+3)(x-3)

LCD: (x+3)(x-3)
2(x+3)-4(x-3)=8
2x+6-4x+12=8
-2x+18=8
-2x=-10
x=5</span>
8 0
3 years ago
25 3/2 in radical form
Crank
Exact Form:
√
25^3

Decimal Form:
125

4 0
3 years ago
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