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Ket [755]
1 year ago
12

PLEASE HELP!! The area of a square is 16 square units. Since 4^2 = 16 and (-4)^2 = 16, both 4 and -4 are square roots for 16. Ex

plain how "both square roots for 16, the area of the square, are the length of each side of the square" is incorrect.
I will mark brainliest!
Mathematics
1 answer:
Rus_ich [418]1 year ago
4 0

we can't say that "both square roots for 16, the area of the square, are the length of each side of the square"

Because one of these solutions does not have a meaning in the given contest.

<h3></h3><h3>Why is the statement incorrect?</h3>

So we have a square with an area of 16 square units, then the side length of that square will be given by:

S^2 = 16 square units

Now, there are two solutions for the above equation, these are:

S = 4 units

S = -4 units.

But being a solution of the equation does not mean that the solutions have sense in the context of the problem.

When we talk about dimensions of figures, negative numbers are not really well defined. We can't say that a square has a side length of "negative 4 units"

That does not make sense, remember that math is just a language, and it should be used to communicate things to others.

So the logical solutions (4 and -4) is not the only thing we need to look at when we state the solutions of a problem, but also the problem itself.

That is why we can't say that "both square roots for 16, the area of the square, are the length of each side of the square"

Because one of these solutions does not have a meaning in the given contest.

If you want to learn more about square roots:

brainly.com/question/98314

#SPJ1

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if a tv has a diagonal measurement of 55 and a height of 30, what is the tvs width? round to the nearest whole number
Sati [7]

Answer:

  46

Step-by-step explanation:

The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.

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<h3>Pythagorean theorem</h3>

The relation between the leg lengths (a, b) and the hypotenuse (c) is ...

  c² = a² +b²

Solving for b gives ...

  b = √(c² -a²)

<h3>application</h3>

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The width of the TV is about 46.

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