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Ket [755]
8 months ago
12

PLEASE HELP!! The area of a square is 16 square units. Since 4^2 = 16 and (-4)^2 = 16, both 4 and -4 are square roots for 16. Ex

plain how "both square roots for 16, the area of the square, are the length of each side of the square" is incorrect.
I will mark brainliest!
Mathematics
1 answer:
Rus_ich [418]8 months ago
4 0

we can't say that "both square roots for 16, the area of the square, are the length of each side of the square"

Because one of these solutions does not have a meaning in the given contest.

<h3></h3><h3>Why is the statement incorrect?</h3>

So we have a square with an area of 16 square units, then the side length of that square will be given by:

S^2 = 16 square units

Now, there are two solutions for the above equation, these are:

S = 4 units

S = -4 units.

But being a solution of the equation does not mean that the solutions have sense in the context of the problem.

When we talk about dimensions of figures, negative numbers are not really well defined. We can't say that a square has a side length of "negative 4 units"

That does not make sense, remember that math is just a language, and it should be used to communicate things to others.

So the logical solutions (4 and -4) is not the only thing we need to look at when we state the solutions of a problem, but also the problem itself.

That is why we can't say that "both square roots for 16, the area of the square, are the length of each side of the square"

Because one of these solutions does not have a meaning in the given contest.

If you want to learn more about square roots:

brainly.com/question/98314

#SPJ1

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HELP!!!! I think its C but I'm not sure!
MA_775_DIABLO [31]

Answer:

The fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. The roots are x=1\pm i\sqrt{7}.

Step-by-step explanation:

Consider the provided information.

Algebra's fundamental theorem states that: Every polynomial equation of degree n with complex coefficients has n roots in the complex numbers.

Now consider the provided equation.

2x^2-4x+16=0

The degree of the polynomial equation is 2, therefore according to Algebra's fundamental theorem the equation have two complex roots.

Now find the root of the equation.

For the quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a=2,\:b=-4,\:\ and \ c=16 in above formula.

x_{1,\:2}=\frac{-\left(-4\right)\pm \sqrt{\left(-4\right)^2-4\cdot \:2\cdot \:16}}{2\cdot \:2}

x_{1,\:2}=\frac{4\pm \sqrt{16-128}}{4}

x_{1,\:2}=\frac{4\pm \sqrt{-112}}{4}

x_{1,\:2}=\frac{4\pm 4i\sqrt{7}}{4}

x_{1,\:2}=1\pm i\sqrt{7}

Hence, the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. The roots are x=1\pm i\sqrt{7}.

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Step-by-step explanation:

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Diano4ka-milaya [45]

In multiplication, the order doesn't matter.

2 rows of 7 and 7 rows of 2 is the same.

If you have seven 2's, that's the same as two 7's.

See here:

2 + 2 + 2 + 2 + 2 + 2 + 2 = 14

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Or:

2 * 7 = 7 * 2 = 14

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Step-by-step explanation:

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