4 years ago

What is the additive inverse of the complex number –8 + 3i?

Mathematics

2 answers:

MariettaO [177]4 years ago

8 0

Answer:

8-3i

Step-by-step explanation:

Lady bird [3.3K]4 years ago

5 0

Choices:
–8 – 3i
–8 + 3i
8 – 3i
<span>8 + 3i

The additive inverse of the complex number a + bi is -(a+bi) = -a - bi

In this case, a = -8 and b = 3i

a + bi = -8 + 3i
additive inverse is: -(-8+3i) = +8 - 3i

The additive inverse of the complex number -8 + 3i is 8 - 3i. The 3rd choice.

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3.920 * (1.018)^x = 5.500<br><br>X=?

Andrei [34K]

Answer:

Step-by-step explanation:

3.920(1.018)ˣ = 5.500

First we can divide both sides by 3.920 to get: (1.108)ˣ = 1.403
Then we can take the natural log of both sides to get: ln[(1.108)ˣ] = ln(1.403)
We can then use logarithmic rules to move the x exponent to the front: xln(1.108) = ln(1.403)
Then we can divide both sides by ln(1.108) to get: $x=\frac{ln(1.403)}{ln(1.018)}$
Then using a calculator we get x = 18.98 ≈19