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enot [183]
3 years ago
7

What is the additive inverse of the complex number –8 + 3i?

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0

Answer:

8-3i

Step-by-step explanation:

Lady bird [3.3K]3 years ago
5 0
Choices:
–8 – 3i
–8 + 3i
8 – 3i
<span>8 + 3i

The additive inverse of the complex number a + bi is -(a+bi) = -a - bi

In this case, a = -8 and b = 3i

a + bi = -8 + 3i
additive inverse is:  -(-8+3i) = +8 - 3i

The additive inverse of the complex number -8 + 3i is 8 - 3i. The 3rd choice.


</span>
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Molly is making peanut butter cookies. To make a batch of cookies she needs cups of peanut butter, 1.5 cups of sugar, and 1 egg.
Rina8888 [55]

Answer:

4 batches

Step-by-step explanation:

one batch calls for:

3/4 PB

1 1/2 cup SG

1 EGG

3/.75(3/4)= 4

9/1.5(1 1/2)=6

5/1= 5

The maximum number of batches she can make before running out of ingredients is 4

6 0
3 years ago
"the life length x (in years) of a dvd player" is exponentially distributed with mean 5 years. what is the probability that a mo
loris [4]
The exponential distribution is:
\lambda e^{- \lambda x}
where \lambda = \frac{1}{mean}=\frac{1}{5}

The probability we want is how likely will a dvd player last more than 8 years, given it has already lasted 5 years
To find this, you use conditional probability.
P(A|B) = \frac{P(A and B)}{P(B)}
where A is P(x>8) and B is P(x>5)
To find these probabilities, integrate over the distribution:
P(x \ \textgreater \ N) = \int_N^{\infty} \frac{1}{5} e^{-x/5} dx = e^{-N/5}

Sub into conditional probability formula:

P(x \ \textgreater \ 8 | x\ \textgreater \ 5) = \frac{P(x\ \textgreater \ 8)}{P(x\ \textgreater \ 5)} = \frac{e^{-8/5}}{e^{-5/5}} = e^{-3/5} = 0.549

Final Answer: Given a dvd player is more than 5 years old, the probability that it will last another 3 more years is about 54.9%
3 0
3 years ago
I NEED HELP QUICKLY!!! What is the sum of the first 140 positive multiples of 3?
garri49 [273]

Answer:

C

Step-by-step explanation:

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3, 6, 9, 12, 15, ...........

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The sum to n terms is

S_{n} = \frac{n}{2} [2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = 3 and d = 3, thus

S_{140} = \frac{140}{2} [ (2 × 3) + (139 × 3) ]

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8 0
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Please help I'm in desperate need of assistance
ivanzaharov [21]

Answer:

Step-by-step explanation: I think for figure 0 is 7.figure 1 is 9 and the growth is for every increase of the figure number it adds 2 for the tile number.

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