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enot [183]
3 years ago
7

What is the additive inverse of the complex number –8 + 3i?

Mathematics
2 answers:
MariettaO [177]3 years ago
8 0

Answer:

8-3i

Step-by-step explanation:

Lady bird [3.3K]3 years ago
5 0
Choices:
–8 – 3i
–8 + 3i
8 – 3i
<span>8 + 3i

The additive inverse of the complex number a + bi is -(a+bi) = -a - bi

In this case, a = -8 and b = 3i

a + bi = -8 + 3i
additive inverse is:  -(-8+3i) = +8 - 3i

The additive inverse of the complex number -8 + 3i is 8 - 3i. The 3rd choice.


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Select True or false for each statement
PilotLPTM [1.2K]

Answer:

False

True

False

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Step-by-step explanation:

1. We have to get the sum as follows :

3\frac{4}{9} + 4\frac{6}{9}

= \frac{31}{9} + \frac{42}{9}

= \frac{31 + 42}{9}

= \frac{73}{9}

= 8\frac{1}{9} \neq  7\frac{1}{9}

So, this is false.

2. We have to get the sum as follows :

4\frac{5}{6} + 1\frac{3}{6}

= \frac{29}{6} + \frac{9}{6}

= \frac{29 + 9}{6}

= \frac{38}{6}

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So, this is true.

3. We have to get the difference as follows :

4\frac{5}{8} - 2\frac{4}{8}

= \frac{37}{8} - \frac{20}{8}

= \frac{37 - 20}{8}

= \frac{17}{8}

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So, this is false.

4. We have to get the difference as follows :

7\frac{5}{8} - 4\frac{2}{8}

= \frac{61}{8} - \frac{34}{8}

= \frac{61 - 34}{8}

= \frac{27}{8}

= 3\frac{3}{8} \neq   3

So, this is also false. (Answer)

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