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Korvikt [17]
3 years ago
14

When comparing the graphs of y = x and y > x , what is a difference in the graph?

Mathematics
1 answer:
Dvinal [7]3 years ago
3 0
Y is the dependent varible and x is the indpendent varible 


have a nice day :)
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At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a
morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = \dfrac{15}{120}=0.125

As we know the poisson process, we get that

P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda

So, for exactly one car would be

P(n=1) is given by

=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

0.2599\times 18=4.6798

We will find the traffic flow q such that

P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%

Hence, a) 4.6798, and b) 19.8%.

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3 years ago
Which table has a constant al proportionality between y and 1.57 Choose 1 answer​
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Which package has the lowest ratio of cost to number of lesson
Ilya [14]

Can you be a little more specific? Put the whole question or something... Hope I can help! :)

4 0
3 years ago
Daniel's yard is perfectly rectangular. It has a length of 28 yards and a perimeter of 88 yards. Find the width of his yard.
Digiron [165]

Draw a picture of the yard, rectangle. On the two long sides, write 28 yards and on the two shorter ones, just write a question mark.

To figure out perimeter, you need to add up each side.

P = Perimeter

L = Length

W = Width

P = L(2) + W(2)

If the length is 28, double it. = 56

Now subtract that from the perimeter - 88-56=32

32 is what you have left, so now split that, and replace the question marks.

All-in-all each width is 16 yards, while each length is 28, making the whole rectangle have a perimeter of 88 yards.

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4 years ago
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