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3 years ago

Break apart and distribute to solve 72÷8 72÷8=(40÷8)+(32÷8) 9=5+4 9=9

Mathematics

2 answers:

ololo11 [35]3 years ago

8 0

You got it right because you solved it correctly

julia-pushkina [17]3 years ago

3 0

Answer:

72 ÷ 8 is equal to 9

Step-by-step explanation:

If we want to solve 72 ÷ 8 by breaking apart and distributing, the first step is to write the number ''72'' as the sum or subtraction of two numbers that are divisible by ''8''.

We can write :

$72 = 40+32$

If we replace this last expression in the original one :

72 ÷ 8 = (40 + 32) ÷ 8 (II)

Now in (II) we can use the distributive property of the division :

(40 + 32) ÷ 8 = (40 ÷ 8) + (32 ÷ 8) (III)

Finally, we need to solve the expression (III) :

(40 ÷ 8) + (32 ÷ 8) = 5 + 4 = 9

We find that 72 ÷ 8 is 9 by breaking apart and then distributing.

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9, 81, 144

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3 years ago

Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

______________________________________________________

TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

SOME GENERAL TRIGNOMETRIC FORMULAS :-

$\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

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______________________________________________________

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

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∴ L.H.S. = R.H.S. (Proved)

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3 years ago

Select the correct answer.

maksim [4K]

Answer: B

Step-by-step explanation:

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3 years ago

Hey guys its me again its me ghriuhr9h so more points yaaaaay

RideAnS [48]

Step-by-step explanation:

thanks for the free points!

have a great day!

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3 years ago

Read 2 more answers

One of the legs of a right triangle is twice as long as the other, and the perimeter of the triangle is 35. Find the

Aloiza [94]

Answer:

6.68, 13.37, 14.95

Step-by-step explanation:

One of the legs is twice as long as the other.

b = 2a

The perimeter is 35.

35 = a + b + c

The triangle is a right triangle.

c² = a² + b²

Three equations, three variables. Start by plugging the first equation into the second and solving for c.

35 = a + 2a + c

c = 35 − 3a

Now plug this and the first equation into the Pythagorean theorem:

(35 − 3a)² = a² + (2a)²

1225 − 210a + 9a² = a² + 4a²

1225 − 210a + 4a² = 0

Solve with quadratic formula:

a = [ -(-210) ± √((-210)² − 4(4)(1225)) ] / 2(4)

a = (210 ± √24500) / 8

a ≈ 6.68 or 45.82

Since the perimeter is 35, a = 6.68. Therefore, the other sides are:

b ≈ 13.37

c ≈ 14.95

8 0

3 years ago